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erastova [34]
4 years ago
10

If the magnitude of the magnetic force on a proton is F when it is moving at 14.0 o with respect to the field, what is the magni

tude of the force (in terms of F) when this charge is moving at 32.5 o with respect to the field?
Physics
1 answer:
sergeinik [125]4 years ago
6 0

Answer:

The magnitude of the magnetic force at 32.5⁰ to the field, is 2.22 F

Explanation:

Given;

magnitude of the magnetic force is F at 14.0⁰ with respect to the field.

To determine the magnitude of the magnetic force at 32.5⁰ to the field, we apply the following formula and solve with proportion;

f*Sin(14.0⁰) = F

f*Sin(32.5⁰) = ?

= \frac{f*Sin(32.5^o)}{f*Sin(14.0^o)}.F\\\\ =2.22 \ F

Therefore, the magnitude of the magnetic force at 32.5⁰ to the field, is 2.22 F

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Answer:0.25 kg-m/s

Explanation:

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The pressure at a certain depth underwater is:

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A = area, d = diameter

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Substitute A:

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F = 1.1×10⁶N

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g = 9.81m/s²

d = 30×10⁻²m

Plug in and solve for h:

h = 1.1×10⁶/(1030(9.81)π(30×10⁻²/2)²)

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