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3 years ago

PLZ HELP

Physics

2 answers:

Sati [7]3 years ago

8 0

Answer:

the index of refraction of the second medium is lower

Explanation:

take an exaple of a light ray from air to water that is optically denser the ray is refracted to the normal thus lowering its index of refraction

xeze [42]3 years ago

3 0

This is what I got on my test

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The mass of jupiter is 300 times the mass of the earth. Jupiter orbits the sun with Tjupiter = 11.9 yr in an orbit with Rjupiter

mihalych1998 [28]

Answer:

c) 11.9 yr

Explanation:

The orbital period is proportional to r^(3/2) and does not depend on the satellite's mass. Any object at Jupiter position will have the same orbital period regardless of mass.

By keppler's law we know that

T^2= r^3

T= orbital time period

r= mean distance of the planet from the Sun.

clearly, The orbital period does not depend on the satellite's mass

there, the correct answer will be c= 11.9 yr.

5 0

3 years ago

A student solving for the acceleration of an object has applied appropriate physics principles and obtained the expression a=a1

AlekseyPX

Explanation:

A student solving for the acceleration of an object has applied appropriate physics principles and obtained the expression :

$a=a_1+\dfrac{F}{m}$

Where

$a_1=3\ m/s^2$

$F=12\ kg-m/s^2$

m = 7 kg

So, the correct step for obtaining a common denominator for the two fractions in the expression in solving for a is (a) and the value of a is :

$a=3+\dfrac{12}{7}$

$a=4.71\ m/s^2$

Hence, the correct option is (a).

8 0

3 years ago

How far will you travel if you run for 10 minutes at 2 m/s?<br><br> SHOW WORK PLZS

ella [17]

10 minutes are the same as 600 seconds.

If you run 2 meters in 1 second then you run 2 * 600 meters in 600 seconds.

7 0

3 years ago

A particle moves along a straight line with equation of motion s = f(t), where s is measured in meters and t in seconds. Find th

Rashid [163]

Answer:

The velocity of the particle = -1.92 m/s

The speed of the particle = 5.72 m/s

Explanation:

Given equation of motion;

$f(t) = 18 \ + \ \frac{48}{t} \ + \ 1$

Velocity is defined as the change in displacement with time.

$V = \frac{df(t)}{dt} = -\frac{48}{t^2} \\\\at \ t = 5 \ s\\\\V = -\frac{48}{5^2} = \frac{-48}{25} = - 1.92 \ m/s$

The distance traveled by the particle in 5 s:

$s = f(5) = 18 + \frac{48}{5} + 1\\\\s= 28.6 \ m$

The speed of the particle when t = 5s

$Speed = \frac{28.6}{5} = 5.72 \ m/s$

6 0

3 years ago

Please I need help on this one kinda lost on it

Vanyuwa [196]

Check the 1st 2nd 3rd and 4th boxes

8 0

3 years ago