A. 30 sixth graders
b. 12 sixth graders
c. If the school has 40 students and the total of students is 70, the number of sixth graders is x
d. 36 students
Answer:
message SHOW_ME_THE_MONEY_
Step-by-step explanation:
The matrix
![A=\left[\begin{array}{cc}1&4\\-1&-3\end{array}\right]\rightarrow |A|=(1 \times -3)-(-1\times 4)=1\\\rightarrow A^{-1}=\left[\begin{array}{cc}-3&-4\\1&1\end{array}\right] \\](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%264%5C%5C-1%26-3%5Cend%7Barray%7D%5Cright%5D%5Crightarrow%20%7CA%7C%3D%281%20%5Ctimes%20-3%29-%28-1%5Ctimes%204%29%3D1%5C%5C%5Crightarrow%20A%5E%7B-1%7D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-3%26-4%5C%5C1%261%5Cend%7Barray%7D%5Cright%5D%20%5C%5C)
We can check that in fact A*A^⁻1=I_2 the identity matrix of size 2 x 2.
Now the message was divided in 1 x 2 matrices, then we have that the sequence given is the result of multiplying m by A, so to get m again we multiply now by A^⁻1. and we get the next table
Encoded message Decoded message message in letters by association
11 52 19 8 S H
-8 -9 15 23 O W
-13 -39 0 13 _ M
5 20 5 0 E _
12 56 20 8 T H
5 20 5 0 E _
-2 7 13 15 M O
9 41 14 5 N E
25 100 25 0 Y _
Then the message decoded is SHOW_ME_THE_MONEY_
Answer: A 729
Step-by-step explanation:
Our first step is to figure out what formulas are needed for diameter, circumference, and area of a circle.
Diameter is simply twice the size of the radius so:
2 * radius = 2 * 40 feet = 80 ft.
Circumference = 2 * pi * radius = 80 ft * pi
If we say that pi = 3.14, then:
circumference = 251.2 ft.
Area = pi * radius^2 = pi * 1600 ft^2
Once again, if we assert pi = 3.14, then:
area = 3.14 * 1600 ft^2 = 5024 ft^2.
Answer:
3/8
Step-by-step explanation: