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2 years ago

10

What is the least common multiple of 4 and 10? 02 0 4 20 40

2 answers:

Setler [38]2 years ago

8 0

Answer:

the answer is 20

viktelen [127]2 years ago

3 0

Answer: 4 I think

Step-by-step explanation:

You might be interested in

If the area of a parallelogram is 9.6cm² and base is 1.2 cm, then the corresponding height is:

julia-pushkina [17]

Answer:

Height is 8cm

Step-by-step explanation:

A= bxh

9.6 = 1.2 x h

÷1.2

8 = h

Check:

8 x 1.2= 9.6cm

Hope this helps!

8 0

3 years ago

Find the length of side AB in the right triangle shown.

Bogdan [553]

Side AB is 72 cm long.

Explanation:

To find the length of side AB you have to use this formula:

${a}^{2} + {b}^{2} = {c}^{2}$

*Remember there are two legs (a and b) and a hypotenuse (c) on a triangle. The longest side will be the hypotenuse and the other two will be the legs. For this triangle the hypotenuse is side BC while the legs are sides CA and side AB.

Plug in the numbers into the equation.

${65}^{2} + {b}^{2} = {97}^{2}$
For this triangle, you were given the hypotenuse (c) and one leg (a). To find the last length solve the equation and balance it so only b is left, like this:

$4225 + {b}^{2} = 9409$

$9409 - 4225 = 5184$

Soo...

${b}^{2} = 5184$

Then to get the side length, square root 5184.

$\sqrt{5184} = 72$

So the length of the last side is 72 cm.

5 0

3 years ago

A right circular cylinder is inscribed in a sphere with diameter 4cm as shown. If the cylinder is open at both ends, find the la

SOVA2 [1]

Answer:

$8\pi\text{ square cm}$

Step-by-step explanation:

Since, we know that,

The surface area of a cylinder having both ends in both sides,

$S=2\pi rh$

Where,

r = radius,

h = height,

Given,

Diameter of the sphere = 4 cm,

So, by using Pythagoras theorem,

$4^2 = (2r)^2 + h^2$ ( see in the below diagram ),

$16 = 4r^2 + h^2$

$16 - 4r^2 = h^2$

$\implies h=\sqrt{16-4r^2}$

Thus, the surface area of the cylinder,

$S=2\pi r(\sqrt{16-4r^2})$

Differentiating with respect to r,

$\frac{dS}{dr}=2\pi(r\times \frac{1}{2\sqrt{16-4r^2}}\times -8r + \sqrt{16-4r^2})$

$=2\pi(\frac{-4r^2+16-4r^2}{\sqrt{16-4r^2}})$

$=2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})$

Again differentiating with respect to r,

$\frac{d^2S}{dt^2}=2\pi(\frac{\sqrt{16-4r^2}\times -16r + (-8r^2+16)\times \frac{1}{2\sqrt{16-4r^2}}\times -8r}{16-4r^2})$

For maximum or minimum,

$\frac{dS}{dt}=0$

$2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})=0$

$-8r^2 + 16 = 0$

$8r^2 = 16$

$r^2 = 2$

$\implies r = \sqrt{2}$

Since, for r = √2,

$\frac{d^2S}{dt^2}=negative$

Hence, the surface area is maximum if r = √2,

And, maximum surface area,

$S = 2\pi (\sqrt{2})(\sqrt{16-8})$

$=2\pi (\sqrt{2})(\sqrt{8})$

$=2\pi \sqrt{16}$

$=8\pi\text{ square cm}$

4 0

3 years ago

40% off sale! Yanika buys a Riding Right mountain bike during the sale. If the original price was $835, how much does Yanika pay

tamaranim1 [39]

501 dollars is the correct answer

5 0

4 years ago

Read 2 more answers

Find the area under the curve y = 13/x3 from x = 1 to x = t. Evaluate the area under the curve for t = 10, t = 100, and t = 1000

zvonat [6]

Answer:

t = 10

$A = 32496.75$

t = 100

$A = 324999996.8$

t = 1000

$A=3.25\times 10^{12}$

Step-by-step explanation:

The area under the curve is calculated by using the following definite integral:

$A = \int\limits^t_ {1} \,{13\cdot x^{3}} dx$

$A = 13 \int\limits^t_1 {x^{3}} \, dx$

$A = \frac{13}{4}\cdot (t^{4}-1)$

Evaluated areas are presented below:

t = 10

$A = 32496.75$

t = 100

$A = 324999996.8$

t = 1000

$A=3.25\times 10^{12}$

8 0

3 years ago