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3 years ago

11

Christine's grade in the three quarters are 88,91,90. if she targets to have an average grade not less then 92 in the four quart

er .what is the least grade she should have for fourth quarter

1 answer:

dezoksy [38]3 years ago

8 0

Total marks C needs to get = 92 x 4 = 368

Least grade (fourth quarter) = 368 - 88 - 91 - 90 = 99

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I need to work out x

frutty [35]

Answer:

9,765 cm

Step-by-step explanation:

We'll solve out the measurements for triangle ABC then it will be easy to figure out x

For triangle ABC, we have

Angle B = 90 degrees.

Angle A (CAB) = 38 degrees (the angle CAD is 19 and is said to be half of CAB, since the line AD is a bisector).

Angle C = 180 - 90 - 38 = 52 degrees.

To find the measurement of the BC line, which we label a, we know that

$\frac{a}{sin(A)} = \frac{c}{sin(c)}$

So, we can isolate the a to get:

$a = \frac{c * sin(A)}{sin(c)} = \frac{25 * sin(38)}{sin(52)} = 19.53$

Now we know the segment BC is 19.53 cm.

And we know that segments CD and DB are equal, since AD is a bisector, cutting the CAB angle in half.

So, CD is half of BC.... so 19.53 / 2 = 9.765 cm

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