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GaryK [48]
3 years ago
11

Christine's grade in the three quarters are 88,91,90. if she targets to have an average grade not less then 92 in the four quart

er .what is the least grade she should have for fourth quarter ​
Mathematics
1 answer:
dezoksy [38]3 years ago
8 0

Total marks C needs to get = 92 x 4 = 368

Least grade (fourth quarter) = 368 - 88 - 91 - 90 = 99

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Read 2 more answers
Maths functions question
yarga [219]

Answer:

a)  OA = 1 unit

b)  OB = 3 units

c)  AB = √10 units

Step-by-step explanation:

<u>Given function</u>:

g(x)=2^x

<h3><u>Part (a)</u></h3>

Point A is the y-intercept of the exponential curve (so when x = 0).

To find the y-value of Point A, substitute x = 0 into the function:

\implies g(0)=2^0=1

Therefore, A (0, 1) so OA = 1 unit.

<h3><u>Part (b)</u></h3>

If BC = 8 units then the y-value of Point C is 8.

The find the x-value of Point C, set the function to 8 and solve for x:

\begin{aligned}f(x) & = 8 \\\implies 2^x & = 8\\2^x & = 2^3\\\implies x &= 3\end{aligned}

Therefore, C (3, 8) so Point B is (3, 0).  Therefore, OB = 3 units.

<h3><u>Part (c)</u></h3>

From parts (a) and (b):

  • A = (0, 1)
  • B = (3, 0)

To find the length of AB, use the distance between two points formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

\textsf{where }(x_1,y_1) \textsf{ and }(x_2,y_2)\:\textsf{are the two points.}

Therefore:

\implies \sf AB=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}

\implies \sf AB=\sqrt{(3-0)^2+(0-1)^2}

\implies \sf AB=\sqrt{(3)^2+(-1)^2}

\implies \sf AB=\sqrt{9+1}

\implies \sf AB=\sqrt{10}\:\:units

5 0
2 years ago
What are the period and amplitude of the function?
Marta_Voda [28]

Answer: it’s a

Step-by-step explanation:

7 0
3 years ago
Someone please help me❤️ Urgently with at least 1
Oksanka [162]

Answer:

See step-by-step explanation

Step-by-step explanation:

Question 3: (4, -3)

Solving through elimination: Multiply the first equation by -3.

-3x+6y=-30

3x-5y = 27

Add. The x drops out.

y= -3

Substitute -3 in for y.

x-2y=10

x-2(-3)=10

x+6=10

x=4

Question 4: (2,5)

Solve through elimination: Multiply the second equation with 3.

\frac{3}{2} x+y=8

\frac{9}{4} x-y=-\frac{1}{2}

3/2= 6/4

15/4x=7.5

x=2

3/2 (2) + y = 8

3+ y =8

y=5

Question 5: (6,4)

Use your graph to graph.

y=-\frac{1}{3} x+6

Slope of -1/3

Y-intercept of 6 (0,6)

X-intercept of 18 (18,0)

y=\frac{3}{2} x-5

Slope of 3/2

Y-intercept of -5 (0,-5)

X-intercept of \frac{10}{3} (

Question 6: (5, -7)

Ax+2By=-41

4Ax-By=88

3A+2B(4)=-41

4A(3)-B(4)=88

Solve by substitution:

Words of encouragement:

Good luck!

8 0
3 years ago
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