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solong [7]
3 years ago
8

How do you label vertices on an image figure?

Mathematics
1 answer:
Fofino [41]3 years ago
4 0
After you get your pre image ploted in the graph then you label your image with a ' such as if your preimage is a then your image is a' 
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If g(x)=3/4x+2,find g(-12)
Triss [41]

Answer:

g(-12) = -7

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The table represents a linear function. Find the values of A and B.​
bazaltina [42]

Answer:

The answers are that a = -5 and b = 1

Step-by-step explanation:

In order to find A and B, we first need to find the equation of the line. We can do this by using two ordered pairs and the slope formula. For the purpose of this activity, I'l use (0, 5) and (-3, 11)

m(slope) = (y2 - y1)/(x2 - x1)

m = (11 - 5)/(-3 - 0)

m = 6/-3

m = -2

Now that we have this we can model this using point-slope form.

y - y1 = m(x - x1)

y - 5 = -2(x - 0)

y - 5 = -2x

y = -2x + 5

Now that we have the modeled equation we can use the ordered pair (a, 15) to solve for a.

y = -2x + 5

15 = -2(a) + 5

10 = -2a

-5 = a

And we can also solve for b using the ordered pair (2, b)

y = -2x + 5

b = -2(2) + 5

b = -4 + 5

b = 1

4 0
3 years ago
Solve y
Ksivusya [100]

The value of y in -3 = 7\left(y-\dfrac97\right) is 6/7

<h3>How to solve for y?</h3>

The equation is given as:

-3 = 7\left(y-\dfrac97\right)

Open the bracket

-3 = 7y - 9

Add 9 to both sides of the equation

7y = 6

Divide both sides by 7

y= 6/7

Hence, the value of y in -3 = 7\left(y-\dfrac97\right) is 6/7

Read more about equations at:

brainly.com/question/2972832

#SPJ1

<u>Complete question</u>

Solve for y

-3 = 7\left(y-\dfrac97\right)

5 0
2 years ago
How many zeros in the standard form of 10/3
Slav-nsk [51]

If you meant, "how many zeros are there in the standard form of 'ten divided by 3,' the answer would be, "none."


10/3 = 3.3333333333333.... This is a repeating decimal.


7 0
4 years ago
7 + (10 − 4)2 ÷ 4 × 1\8
natta225 [31]
I’m pretty sure the answer is 12

6 0
3 years ago
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