$ln(T- \frac{20}{200})=-0.11t \\ e^{ln(T- \frac{20}{200})}=e^{-0.11t} \\ T- \frac{20}{200} =e^{-0.11t} \\ T-0.1=e^{-0.11t} \\ T=e^{-0.11t}+0.1$
Then, now that we have solved for T, we can evaluate and solve for t=20 minutes.
$T=e^{-0.11t}+0.1 \\ T=e^{-0.11*20}+0.1 \\ T=e^{-2.2}+0.1 \\ T=0.11+0.1 \\ T=0.21$

7 0

3 years ago

In its Fuel Economy Guide for 2014 model vehicles, the Environmental Protection Agency gives data on 1160 vehicles. There are a

MrRissso [65]

Step-by-step explanation:

wait can you show a picture of your work so I can see what percent of all vehicles have better gas or mileage than the Beetle

8 0

3 years ago

A researcher reports that there is no consistent relationship between grade point average and the number of hours spent studying

lora16 [44]

Answer:

a correlation near 0

Step-by-step explanation:

7 0

3 years ago