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2 years ago

use the numbers and decimals to write a number in which the digital 2 is one tenth the value of the digital 2 in 8.524

Mathematics

2 answers:

PilotLPTM [1.2K]2 years ago

3 0

It is in 20 ...........................

babunello [35]2 years ago

3 0

20 so in other words it would be 2hundredths.

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Help: 10 points!! 13=n+ 3/fourths

disa [49]

Answer:

n = 12 1/4

Step-by-step explanation:

do you need me to explain it too? I can! XD ^_^

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3 years ago

A music club has 35 drum players. If 25% of the total number of members in the club are drum players, what is the total number o

Pachacha [2.7K]

Answer:

140

Step-by-step explanation:

Since 25% is 1/4 of 100, that means that 35 is 1/4 of the total amount of members in the club. So, 35 times 4 is 140.

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3 years ago

What was the cost of a ticket to ride the original Ferris wheel

HACTEHA [7]

Answer:

100

Step-by-step explanation:

100 is the correct answer

5 0

2 years ago

Read 2 more answers

Write one hundred twenty-three and fourteen thousandths as a decimal number.

DochEvi [55]

Answer:

.12314

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Derivative of<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7B3x%7D%5E%7B2%7D%20-%202x%20-%201%20%7D%7B%20%7Bx%7D%5E%7B2

Anastaziya [24]

Answer:

$\displaystyle \frac{dy}{dx} = \frac{2x + 2}{x^3}$

Step-by-step explanation:

we would like to figure out the derivative of the following:

$\displaystyle \frac{ { 3x }^{2} - 2x - 1 }{ {x}^{2} }$

to do so, let,

$\displaystyle y = \frac{ { 3x }^{2} - 2x - 1 }{ {x}^{2} }$

By simplifying we acquire:

$\displaystyle y = 3 - \frac{2}{x} - \frac{1}{ {x}^{2} }$

use law of exponent which yields:

$\displaystyle y = 3 - 2 {x}^{ - 1} - { {x}^{ - 2} }$

take derivative in both sides:

$\displaystyle \frac{dy}{dx} = \frac{d}{dx} (3 - 2 {x}^{ - 1} - { {x}^{ - 2} } )$

use sum derivation rule which yields:

$\rm\displaystyle \frac{dy}{dx} = \frac{d}{dx} 3 - \frac{d}{dx} 2 {x}^{ - 1} - \frac{d}{dx} {x}^{ - 2}$

By constant derivation we acquire:

$\rm\displaystyle \frac{dy}{dx} = 0 - \frac{d}{dx} 2 {x}^{ - 1} - \frac{d}{dx} {x}^{ - 2}$

use exponent rule of derivation which yields:

$\rm\displaystyle \frac{dy}{dx} = 0 - ( - 2 {x}^{ - 1 -1} ) - ( - 2 {x}^{ - 2 - 1} )$

simplify exponent:

$\rm\displaystyle \frac{dy}{dx} = 0 - ( - 2 {x}^{ -2} ) - ( - 2 {x}^{ - 3} )$

two negatives make positive so,

$\displaystyle \frac{dy}{dx} = 2 {x}^{ -2} + 2 {x}^{ - 3}$

<h3>further simplification if needed:</h3>

by law of exponent we acquire:

$\displaystyle \frac{dy}{dx} = \frac{2 }{x^2}+ \frac{2}{x^3}$

simplify addition:

$\displaystyle \frac{dy}{dx} = \frac{2x + 2}{x^3}$

and we are done!

5 0

2 years ago