Line AB and Line BC are tangent to P. What is the value of x? 73 107 117 146

How do I solve -4-(2m+3)=-m-(5+3m)

drek231 [11]

-4-(2m+3)=-m-(5+3)
-4-2m-3=-m-5-3m
-2m-7=-4m-5
-2m+4m=-5+7
2m=2
m=2/2
m=1

3 0

2 years ago

Write the equation of a line that has a slope of -3 and goes through the point (5,7).

ss7ja [257]

Answer:

The equation of the line would be D) y - 7 = -3(x -5)

Step-by-step explanation:

In order to find this, we must first start with the base form of point-slope form.

y - y1 = m(x - x1)

Now we put the slope in for m and the point in for (x1, y1)

y - 7 = -3(x - 5)

6 0

3 years ago

When you multiply a function by -1 what is the effect on its graph?

vlada-n [284]

Answer:

Step-by-step explanation:

Depends on what you mean by multiplying by - 1. I assume you are not going to multiply the y or f(x) term by - 1.

If that is so, take an example. Suppose you have a graph that is y=x^2

That's a parabola that opens upwards and it has a line going through its focus which is a point on the +y axis.

When you multiply the right hand side by - 1, the graph you get will be y = - x^2.

That opens downward and the focus is on the - y axis.

That means that the effect of the graph is that it flips over the x axis, which I think is the third answer.

5 0

3 years ago

An automotive manufacturer has developed a new type of tire that the research team believes to increase fuel efficiency. The man

Stolb23 [73]

Answer:

One tailed

To conclude if there is an increase in the mean gas mileage due to new type of tire.

Step-by-step explanation:

We are given the following in the question:

The manufacture wants to compare increase in the mean gas mileage.

Population mean = 32 miles per gallon

Thus, the manufacture could carry a hypothesis test to compare mean.

A one tailed test (z-test or t-test) based on the information can be used to compare the increase in mean.

Thus,

The automotive manufacturer should perform a one tailed hypothesis test to conclude if there is an increase in the mean gas mileage due to new type of tire.

6 0

3 years ago

Computer keyboard failures are due to faulty electrical connects (12%) or mechanical defects (88%). Mechanical defects are relat

anzhelika [568]

Answer:

(c) Probability that a failure is due to loose keys = 0.2376

(d) Probability that a failure is due to improperly connected or poorly welded wires = 0.078

Step-by-step explanation:

The Whole probability scenario is given for Computer Keyboard failures.

(a) Let F be the event of failure due to faulty electrical connects, P(F) = 0.12

M be the event of failure due to mechanical defects, P(M) = 0.88

LK be the event of mechanical defect due to loose keys, P(LK/M) = 0.27

IA be the event of mechanical defect due to improper assembly, P(IA/M) =0.73

DW be the event of electrical connects due to defective wires,P(DW/F) = 0.35

IC be the event of electrical connects due to improper connections,

P(IC/F) = 0.13 .

PWW be the event of electrical connects due to poorly welded wires,

P(PWW/F) = 0.52

(b) Keyboard failures

Faulty electrical connects Mechanical Defects

P(F) = 0.12 P(M) = 0.88

Defective wires Improper Poorly Loose Keys Improper

P(DW/F)=0.35 Connections Welded wires P(LK/M)=0.27 Assembly

P(IC/F)=0.13 P(PWW/F)=0.52 P(IA/M)=0.73

This is the required tree diagram.

(c) Probability that a failure is due to loose keys is given by:

P(LK) =P(LK/M) * P(M) {This means mechanical failure is due to loose

keys}

P(LK) = 0.27 * 0.88 = 0.2376 .

(d) Probability that a failure is due to improperly connected or poorly welded

wires is given by P(IC $\bigcup$ PWW) ;

P(IC $\bigcup$ PWW) = P(IC) + P(PWW) - P(IC $\bigcap$ PWW) { Here P(IC $\bigcap$ PWW) = 0 }

P(IC) = P(IC/F) * P(F) = 0.13 * 0.12 = 0.0156

P(PWW) = P(PWW/F) * P(F) = 0.52 * 0.13 = 0.0676

Therefore, P(IC $\bigcup$ PWW) = 0.0156 + 0.0676 - 0 = 0.078 .

8 0

3 years ago