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Crank
3 years ago
9

How many solutions does this system of two equations shown have ? y=3(x+4) y=3(x-4)

Mathematics
1 answer:
alisha [4.7K]3 years ago
7 0

Answer:

One Soulution for both they are parallel and never meet

Step-by-step explanation:

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Help please! ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!
solmaris [256]

Answer:

x= 1/2

and y=3

Step-by-step explanation:

Let's solve your system by substitution.

y=10x−2;2x+y=4

Step: Solvey=10x−2for y:

y=10x−2

Step: Substitute10x−2foryin2x+y=4:

2x+y=4

2x+10x−2=4

12x−2=4(Simplify both sides of the equation)

12x−2+2=4+2(Add 2 to both sides)

12x=6

12x

12

=

6

12

(Divide both sides by 12)

x=

1

2

Step: Substitute

1

2

forxiny=10x−2:

y=10x−2

y=10(

1

2

)−2

y=3(Simplify both sides of the equation)

Answer:

x= 1 /2

and y

3 0
3 years ago
Perimeter of a rectangular room is 270 yards. Longer side of the room is 15 yards longer than the shorter side. Find the dimensi
ankoles [38]

In this question , it is given that, Perimeter of a rectangular room is 270 yards. Longer side of the room is 15 yards longer than the shorter side.

So if we let shorter side be x, then longer side is

x+15

And perimeter is equal to sum of all sides, that is

x+x+15+x+x+15=270
\\
4x+30=270
\\
4x=240
\\
x=60

So the smaller side is 60 yards , and longer side is 15 more then 60 that is 75 yards .

4 0
3 years ago
Read 2 more answers
Convert yards used for concrete to metric
pentagon [3]

Answer: no way

Step-by-step explanation: you add x plus yyy

5 0
3 years ago
The area of a square piece of cardboard is 81 square inches. What is the length of the cardboard?
Marianna [84]

Answer:

Step-by-step explanation:

The area of a square is found in the formula

A=s^2

We have the Area value so we will plug it in:

81=s^2

Take the square root of both sides to undo the square on the s to get that

s = 9

8 0
4 years ago
A real estate company wants to build a parking lot along the side of one of its buildings using 400 feet of fence. If the side a
svetlana [45]

Answer:

1.) Therefore the side parallel to the building is 100 feet.

2.) The side perpendicular to the building is 200 feet.

Step-by-step explanation:

The parking lot, which is rectangular,  is built along the side of one of its buildings.

The side of the parking lot which is alongside the building needs no fence,

let us say that this side is of length y.

Let the perpendicular to the building be of length x.

The perimeter of the parking lot that actually needs to be fenced  = 2x + y

The amount of fencing available  = 400 feet.

Therefore 2x + y = 400    ....    (i)

Therefore y = 400 - 2x     ....    (ii)

The area of the parking lot, A = xy   =   x ( 400 - 2x)  =   400x - 2x^2   ....   (iii)

Therefore \frac{dA}{dx}  = \frac{d(400x - 2x^2}{dx}  = 400 - 4x     ....   (iv)

Also we get \frac{d^2A}{dx^2}  = -4     ....    (v)

Hence we will get the maximum value of the parking lot by equating the first order differential of area, A to zero as the second order differential of area, A is negative.

Therefore from (iv) we get 400 - 4x  = 0     ∴ x = 100 feet

y  = 400 - 2x = 400 - 200 = 200 feet.

1.) Therefore the side parallel to the building is 100 feet.

2.) The side perpendicular to the building is 200 feet.

6 0
4 years ago
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