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stealth61 [152]

4 years ago

11

Which are coplanar and noncolinar?

1 answer:

Paul [167]4 years ago

3 0

<em>Coplanar</em> means "lying on the same plane," while <em>colinear </em>means "lying on the same line." In this problem, all four points A, B, C, and D are coplanar - they all lie on the plane $\mathcal{H}$ - so we just need to find the points that lie on the same line. Though points C and B <em>would </em>be colinear if there was a line drawn between them, there's no such line in this problem, so we can rule that out. We notice one line drawn on the plane, and points A, C, and D lying on it, so we can say that points A, C, and D are both coplanar and colinear.

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Select all of the following expressions that are equivalent to 9 1/2

muminat

(1)

(3)

(4)

I think im sorry if im wrong too

8 0

3 years ago

If AABC = ADEC,<br> LC = 55°, ZD = 65°, and ZB = 2x<br> D<br> С<br> В B.<br> x = [?]

elena55 [62]

Answer:

x = 30

Step-by-step explanation:

65 + 55 = 120

angle B must equal 60

angle B is labeled as 2x

set up equation to solve for 'x': 2x = 60

x = 30

add up all angles to make sure you get 180 degrees

6 0

3 years ago

Y=x² + 16x + 64

motikmotik

I'll do the first one to get you started

The equation y = x^2+16x+64 is the same as y = 1x^2+16x+64

Compare that to y = ax^2+bx+c and we see that

a = 1

b = 16

c = 64

Use the values of 'a' and b to get the value of h as shown below

h = -b/(2a)

h = -16/(2*1)

h = -8

This is the x coordinate of the vertex.

Plug this x value into the original equation to find the corresponding y value of the vertex.

y = x^2+16x+64

y = (-8)^2 + 16(-8) + 64

y = 0

Since the y coordinate of the vertex is 0, this means k = 0.

The vertex is (h,k) = (-8, 0)

---------------------

So we found that a = 1, h = -8 and k = 0

Therefore,

f(x) = a(x-h)^2 + k

f(x) = 1(x-(-8))^2 + 0

f(x) = (x+8)^2

is the vertex form

---------------------

<h3>Final answer to problem 1 is f(x) = (x+8)^2 </h3>

8 0

3 years ago

PLS ANSWER ITS URGENT

matrenka [14]

Answer:

The length of the ramp must be at least 14.71 feet

Step-by-step explanation:

Given

$BC = 2.3ft$

$\theta = 9^\circ$

<em>See attachment for complete figure</em>

Required

Length of the ramp (z)

To do this, we consider sin of angle A ( $\theta$ ).

So, we have:

$sin\theta = \frac{Opposite}{Hypotenuse}$

This gives:

$sin(9)= \frac{2.3}{z}$

Make z the subject

$z= \frac{2.3}{sin(9)}$

$z = \frac{2.3}{0.1564}$

$z = 14.71 ft$

<em>The length of the ramp must be at least 14.71 feet</em>

6 0

3 years ago

The reference angle for 4pie/3 is pie/3, which has a terminal point of (1/2, square3/2) .What is the terminal point for 4pie/3 ?

asambeis [7]

Answer:

B

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers