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3 years ago

write a real-world problem that can be represented by the equation (12+14)×h over 2= 52. Then solve the problem.

Mathematics

1 answer:

jek_recluse [69]3 years ago

6 0

(12+14)x h
-------------- = 52
2

26h = 104
h =4

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Need answer asap I’m timed!!!

Ugo [173]

Should be option 1. i cant really gv an explanation tho sry :/

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4 years ago

A cone shaped paper water cup has a height of 12 cm and a radius of 6 cm. If the cup is filled with water to half its height, wh

monitta

Answer:

The portion of the volume of the cup that is filled with water is $\frac{1}{8}$

Step-by-step explanation:

step 1

Find the volume of the paper water cup

The volume of the cone is equal to

$V=\frac{1}{3}\pi r^{2}h$

we have

$r=6\ cm$

$h=12\ cm$

substitute

$V=\frac{1}{3}\pi (6)^{2}(12)$

$V=144\pi\ cm^{3}$

step 2

If the cup is filled with water to half its height, find out what portion of the volume of the cup is filled with water

Remember that

If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube

In this problem the similar cone has half the height of the complete cone

The scale factor is equal to 1/2

therefore

The volume of the cup that is filled with water is equal to the volume of the complete cup by the scale factor elevated to the cube

$V=(1/2)^{3}(144\pi)=(1/8)144\pi\ cm^{3}$

therefore

The portion of the volume of the cup that is filled with water is

$\frac{1}{8}$

8 0

3 years ago

Read 2 more answers

Answer and explanation?

bazaltina [42]

C!
One dollar = $1
And in a math equation is usually a decimal
56 cents is .56 because it’s not a whole new If you add them together you get $1.56 :) hope it helps

8 0

3 years ago

Find a counter example If 6x-3 > 1 then x > 2

Otrada [13]

Answer:

if x=1

Step-by-step explanation:

6(1)-3>1, then (1)> 2

3>1 then 1>2 (not true)

8 0

3 years ago

Let $r$ and $s$ be the roots of $3x^2 + 4x + 12 = 0.$ Find $r^2 + s^2.$ Pls help.

nirvana33 [79]

Answer:

-56/9

Step-by-step explanation:

By Vieta's formulas,

$r + s = -\frac{4}{3}$ and $rs = \frac{12}{3} = 4.$ Squaring the equation $r + s = -\frac{4}{3},$ we get

$r^2 + 2rs + s^2 = \frac{16}{9}.$ Therefore,

$r^2 + s^2 = \frac{16}{9} - 2rs = \frac{16}{9} - 2 \cdot 4 = -\frac{56}{9}}$

5 0

3 years ago