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2 years ago

Let $r$ and $s$ be the roots of $3x^2 + 4x + 12 = 0.$ Find $r^2 + s^2.$ Pls help.

Mathematics

1 answer:

nirvana33 [79]2 years ago

5 0

Answer:

-56/9

Step-by-step explanation:

By Vieta's formulas,

$r + s = -\frac{4}{3}$ and $rs = \frac{12}{3} = 4.$ Squaring the equation $r + s = -\frac{4}{3},$ we get

$r^2 + 2rs + s^2 = \frac{16}{9}.$ Therefore,

$r^2 + s^2 = \frac{16}{9} - 2rs = \frac{16}{9} - 2 \cdot 4 = -\frac{56}{9}}$

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Step-by-step explanation:

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2 years ago

What is the length of AE 1. 17.1 2. 23.39 3. 22.9 4. 43.39

jonny [76]

I hope this helps you

17,1/17,1+20=20/20+AE

17,1/37,1=20/20+AE

171/371=20/20+AE

20+AE=20.371/171

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AE=23,39

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