Here we have a case of the least common multipl(lcm) of 6 and 20.
Prime numbers 2,3,5,7,11,13,17,19... (natural numbers greater than 1 that has no positive divisors other than 1 and itself) .
lcm(6,20)= 6 20 | 2
3 10 | 3
1 10 | 2
5 | 5
1
2*3*2*5=60 The first one to get both calendar and the animal toy will be 60th.
Explenation: First we look for the smallest prime number with wich 6 and 20 can be devided by. That is 2. Next is 3. Since 10 is not divisible by 3, we only copy it. Under the 6 we got 1, wich is our goal. Now we continue to devide 10 by prime numbers till we also get 1. We now multiple all divisors and we get the least common multiple.
Answer:
The correct answer is B
Step-by-step explanation:
First, the question said that the shoes were $15 less than double the price of his pants. In algebra 2p would mean 2 multiplied by p so we know that C and D are wrong. Now $15 less than 2p would mean you have to subtract by 15, so now we have 2p-15. Since we haven't added in the amount of money the pair of pants cost, we have to use addition to add it in, and that adds to the equation making the equation 2p - 15 + p. So, the answer is B.
I search and found different answers but the nearest is 24
Answer:
The last one
Step-by-step explanation:
measure angle 2 and 6 to see if congruent
Answer:
g
Step-by-step explanation:
