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3 years ago

the rectangle poster shown at the right measures 2w-30 by w. the poster has an area of 5400 cm^2. what is the value of a?

2 answers:

6 0

This is the concept of algebra, to get the values of the unknown we proceed as follows:
Length=(2w-30) cm
width=w
Area=length×width
=w(2w-30)=5400
=2w^2-30w=5400
hence
2w^2-30w-5400=0
solving the quadratic we get:
w^2-15w-2700=0
thus
(w+45)(w-60)=0
hence
w=-45 or w=60
since there is no negative dimension we shall take w=60
thus the value of w=60

serg [7]3 years ago

5 0

Answer:

w=60

Step-by-step explanation:

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3 years ago

the price of a new pair of sneakers is $79.95. if sales tax is 7.5%, then approximately, how much tax will be paid on sneakers?

Firlakuza [10]

Answer:

Step-by-step explanation:

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4 years ago

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arlik [135]

Answer:

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Step-by-step explanation:

Given,

Density of copper ( D ) = 8960 kg / m³

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Formula : -

Volume of cube = l³

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2 years ago

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polet [3.4K]

Answer: (a) IV (b) positive (c) $\frac{\pi}{4}$ (d) C (e) $\sqrt{2}$

Step-by-step explanation:

a) $\frac{15\pi}{4}$ - $\frac{8\pi}{4}$ = $\frac{7\pi}{4}$ , which is located in Quadrant IV per the Unit Circle.

b) sec is $\frac{1}{cos}$ . Cos is the x-coordinate. The x-coordinate inQuadrant IV is positive.

c) the reference angle is the angle from $\frac{7\pi}{4}$ to 2π = $\frac{\pi}{4}$

d) since the angle is below the x-axis and the reference angle is $\frac{\pi}{4}$ , then the angle is equal to $-sec(\frac{\pi}{4}$ )

e) sec = $\frac{1}{cos}$ ⇒ sec $\frac{7\pi}{4}$ = $\frac{2}{\sqrt{2} }$ = $\frac{2}{\sqrt{2} }$ $(\frac{\sqrt{2}} {\sqrt{2}})$ = $\frac{2\sqrt{2} }{2}$ = $\sqrt{2}$