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Bingel [31]
3 years ago
10

H(x) = x2 – 3

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
4 0

Answer:

g(x)=x^2+1

Step-by-step explanation:

The given function is

h(x)=x^2-3

If a function translated vertically upward by p units, then we need to add p in the function value to get the new function.

It is given that if the graph of h is translated vertically upward by 4 units, it becomes the graph of a function g. So,

g(x)=h(x)+4

g(x)=x^2-3+4

On simplification, we get

g(x)=x^2+1

Therefore, the required function is g(x)=x^2+1.

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HELP PLZZZZZZZZZZZZZZXZXXXZZZZXZZX
meriva

Answer:

c

Step-by-step explanation:

4×2=2in

100÷2=50%

so it is c

5 0
3 years ago
Read 2 more answers
3. Nancy and Harry are sliding a stone statue and moving it to a new location in their garden. Nancy is pushing the statue with
Elis [28]

Answer:

197,8879 N.

Step-by-step explanation:

The magnitude of the horizontal force exerted on the statue can be calculated using trigonometric functions.

The question given says that Nancy is pushing the statue with a force of 120 N at a 60° angle to the horizontal and Harry is pulling the statue with a force of 180 N at a 40° angle with the horizontal.

With that information can be calculated the horizontal force exerted on the statue by Nancy, the horizontal force exerted on the statue by Harry and, adding that results, the total horizontal magnitude can be calculated.

The cosine function can be used to calculate the horizontal component of the forces exerted by Nancy and Harry, to determine the horizontal component of the force exerted on the statue.

F= (120 N cos 60°) + (180 N x cos 40°)

F= 197,8879 N

5 0
3 years ago
Q18. The sum of the first N terms of an arithmetic series, S, is 292 The 2nd term of S is 8.5 The 5th term of Sis 13 Find the va
Gelneren [198K]

Step-by-step explanation:

Sn= a+[n-1]d

S2= a+[2-1]d

8.5 = a+d _______Equation 1

S5 = a+[5-1]d

13=a+4d ________Equation 2

Subtract Equation 1 from Equation 2

13=a+4d

-

8.5= a+d

________

4.5= 3d

d=1.5

Substituting d=1.5 in equation 1

8.5=a+1.5

a=8.5-1.5

a=7

Sum of terms of an A.P =

Sn= n/2[2a+(n-1)d]

292= n/2[2×7+(n-1)d]

292=n/2[14+(n-1)1.5

292×2=n[14+(n-1)1.5]

584=n[14+1.5n-1.5]

584= 14n+1.5n²-1.5n

584= 1.5n²+12.5n

1.5n²+12.5n-584

1.5n²-24n+36.5n-584

1.5n(n-16)+36.5(n-16)

(1.5n+36.5)(n-16)

**n-16=0

n=16

3 0
1 year ago
F(x)=3x 2+x<br><br><br> Find f(−5)
Zina [86]

\huge \boxed{\mathfrak{Question} \downarrow}

  • f (x) = 3x² + x
  • Find f (-5).

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

Given,

  • f (x) = 3x² + x

Now, we have to find f (-5). To find this, we just need to substitute -5 in the place of x.

So,

\sf \: f(x) =  {3x}^{2}  + x \\  \\ \sf \: \: Substitute \: x \: as \:  - 5. \\  \\ \sf \:f( - 5) = 3( - 5) ^{2}  + ( - 5) \\ \\  \sf \:Calculate \:  -5 \:  to \:  the \:  power  \: of \:  2 \:  and \:  get \:  25. \\  \\\sf \: 3\times 25+5  \\  \\ \sf \:Multiply \:  3 \:  and \:  25 \:  to \:  get \:  75. \\ \\\sf \:  75+5  \\  \\\sf \:Add \:  75 \:  and \:  5  \: to  \: get  \: 80. \\   \\  =   \boxed{\boxed{ \bf \: 80}}

5 0
3 years ago
a rectangular pool has an area of 640 square feet. the is 12 feet shorter than the width. the length of the pool is feet and the
Ray Of Light [21]

Given:

Area of rectangular pool = 640 square feet

The length is 12 feet shorter than the width.

To find:

The length and width of the pool.

Solution:

Let width of the pool = x feet

Then, Length of the pool = (x-12) feet

Area of a rectangle is

Area=length\times width

Area=(x-12)\times x

Area of pool is 640 square feet. So,

(x-12)x=640

x^2-12x-640=0

Splitting the middle term, we get

x^2-32x+20x-640=0

x(x-32)+20(x-32)=0

(x+20)(x-32)=0

Using zero product property, we get

x=-20,32

Dimensions cannot be negative. So, x=32.

Now,

Width of the pool = 32 feet

Length of the pool = 32-12 = 20 feet

Therefore, the length of the pool is 20 feet and width is 32 feet.

7 0
3 years ago
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