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bekas [8.4K]
3 years ago
12

What is the value of this expression? (−4)4

Mathematics
2 answers:
alisha [4.7K]3 years ago
7 0
It should be -16, assuming you are asking for -4*4. If you meant -4^4 (-4 to the fourth power) then the answer is 256.
olchik [2.2K]3 years ago
3 0
The question is asking for the product of these two terms.

First you need to consider the sign, remember the following rules:
positive * positive = positive
negative * negative = negative
positive * negative = negative
negative * positive = negative

In the question, we have a negative term and a positive term, therefore, the answer would be negative.
Now considering the two numbers: 4*4 = 16

Based on the above and taking the sign into consideration, the answer would be as follows:
(-4)(4) = -16
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Help needed....
LenKa [72]
The answer is C) y = 4x - 3
B and D can be eliminated by substituting 0 for x in each...the result is not -3
Now you have a 50/50 chance of getting the question correct
5 0
4 years ago
A boy weighs 22.5 kilograms. How much does he weigh in pounds? Use the following conversion: 1 kilogram is 2.2 pounds.
salantis [7]

22.5 x 2.2 = 49.5 pounds

4 0
3 years ago
The diagram shows a 5 cm x 5 cm x 5 cm cube.
mylen [45]

Answer:

~8.66cm

Step-by-step explanation:

The length of a diagonal of a rectangular of sides a and b is

\sqrt{a^2+b^2}

in a cube, we can start by computing the diagonal of a rectangular side/wall containing A and then the diagonal of the rectangle formed by that diagonal and the edge leading to A. If the cube has sides a, b and c, we infer that the length is:

\sqrt{\sqrt{a^2+b^2}^2 + c^2} = \sqrt{a^2+b^2+c^2}

Using this reasoning, we can prove that in a n-dimensional space, the length of the longest diagonal of a hypercube of edge lengths a_1, a_2, a_3, \ldots, a_n is

\sqrt{a_1^2 + a_2^2 + a_3^2 + \ldots + a_n^2}

So the solution here is

\sqrt{(5cm)^2 + (5cm)^2 + (5cm)^2} = \sqrt{75cm^2} = 5\sqrt{3cm^2} \approx 5\cdot 1.732cm = 8.66cm

5 0
3 years ago
Read 2 more answers
Given: AC and AE are common external tangents of G and D. BC= 123 GB=20 and AG=101. What is the measure of AC?​
Solnce55 [7]

Answer:

The length of AC is 222 units.

Step-by-step explanation:

Given AC and AE are common external tangents of G and D.

BC= 123 ,  GB=20 and AG=101.

We have to find the measure of AC.

As, a straight line joined from the center i.e radius is perpendicular to tangent drawn. Therefore,

In ΔABG, by Pythagoras theorem

AG^2=AB^2+BG^2

⇒ 101^2=AB^2+20^2

⇒ AB^2=10201-400=9801

⇒ AB=99 units.

Hence, AC=AB+BC=99+123=222 units.

The length of AC is 222 units.

8 0
3 years ago
Solve the quadratic function by factoring. You must fill in
Stells [14]

Answer:

5x+2=0

Step-by-step explanation:

When factoring you add or subtract your factors that are similar.

For example 9x-4x+ 5x

and this is how you get 5x+2=0

Any Questions?

4 0
3 years ago
Read 2 more answers
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