All categories

3 years ago

The atomic mass of carbon is 12.01, hydrogen is 1.01, and oxygen is 16.00. What is the molar mass of glucose (C6H12O6)?

Chemistry

2 answers:

Sladkaya [172]3 years ago

6 0

Answer:

180.18 g/mol is the molar mass of glucose.

Explanation:

Molar mass is defined as the sum of the mass of all the atoms each multiplied its atomic masses that are present in the molecular formula of a compound. It is expressed in g/mol.

Atomic mass of carbon = 12.01 g/mol

Atomic mass of hydrogen = 1.01 g/mol

Atomic mass of oxygen = 16.00 g/mol

Molecular formula of glucose = $C_6H_{12}O_6$

Molar mass of glucose:

$=6\times 12.01 g/mol+12\times 1.01 g/mol+6\times 16.00 g/mol$

= 180.18 g/mol

kotykmax [81]3 years ago

4 0

To find out the molar mass, you have to break down each of the elements, then add them up.

C6 = 12.01 x 6 = 72.06 (Beacause, there are 6 carbon atoms)
H12 = 1.01 x 12 = 12.12 (Because, there are 12 hydrogen atoms)
O6 = 16.00 x 6 = 96 (Because there are 6 oxygen atoms)

Now, you will add all three of the elements up: 72.06 + 12.12 + 96 = 180.18.

So the molar mass of glucose is 180.18.

You might be interested in

Would you like Brainliest?

lubasha [3.4K]

Answer:

yes please

Explanation:

6 0

2 years ago

Read 2 more answers

In thermodynamics, we determine the spontaneity of a reaction by the sign of ΔG. In electrochemistry, spontaneity is determined

faltersainse [42]

Answer:

For A: The standard cell potential of the reaction is 4.4 V

For B: The standard Gibbs free energy of the reaction is $-8.50\times 10^5J$

For C: The reaction is spontaneous as written.

Explanation:

For A:

The given chemical reaction follows:

$2Li(s)+Cl_2(g)\rightarrow 2Li^+(aq.)+2Cl^-(aq.)$

The given half reaction follows:

Oxidation half reaction: $Li(s)\rightarrow Li^+(aq.)+e^-;E^o_{Li^+/Li}=-3.04V$ ( × 2)

Reduction half reaction: $Cl_2(g)+2e^-\rightarrow 2Cl^-(aq.);E^o_{Cl_2/2Cl^-}=+1.36V$

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction.

Here, chlorine will undergo reduction reaction will get reduced.

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

$E^o_{cell}=1.36-(-3.04)=4.4V$

Hence, the standard cell potential of the reaction is 4.4 V

For B:

Relationship between standard Gibbs free energy and standard electrode potential follows:

$\Delta G^o=-nFE^o_{cell}$

where,

n = number of electrons transferred = $2mol\text{ e}^-$

F = Faradays constant = $96500J/V.mol\text{ e}^-$

$E^o_{cell}$ = standard cell potential = 4.4 V

Putting values in above equation, we get:

$\Delta G^o=-2\times 96500\times 4.4=-849200J=-8.50\times 10^5J$

Hence, the standard Gibbs free energy of the reaction is $-8.50\times 10^5J$

For C:

For a reaction to be spontaneous, the standard Gibbs free energy change of the reaction must be negative.

From above, the standard Gibbs free energy change of the reaction is coming out to be negative.

Hence, the reaction is spontaneous as written.

7 0

4 years ago

When sodium and oxygen react to form an ionic compound, the mass of the compound ____ the sum of the masses of the individual el

Anna007 [38]

Hi Lara

The answer is : C

Is equal to

I hope that's help!

5 0

4 years ago

Read 2 more answers

HELP QUICK ASSESMENT

ehidna [41]

Answer:

MAGNESIUM

Explanation:

7 0

3 years ago

Read 2 more answers

What is formed when hydrobromic acid, hbr, and calcium hydroxide, ca(oh)2, are combined?

Lorico [155]

This is an acid – base reaction and this always result a salt and water in a neutralization reaction. 

The salt that is formed will be calcium bromide (calcium is located in group 2 so calcium bromide has a formula of CaBr2)

so essentially we got:

HBr + Ca(OH)2 ------> CaBr2 + H2O

balancing the elements: 

2HBr(aq) + Ca(OH)2(aq) --------> CaBr2(aq) + 2H2O(l)

6 0

3 years ago