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BaLLatris [955]
2 years ago
9

What is formed when hydrobromic acid, hbr, and calcium hydroxide, ca(oh)2, are combined?

Chemistry
1 answer:
Lorico [155]2 years ago
6 0

This is an acid – base reaction and this always result a salt and water in a neutralization reaction. <span>

The salt that is formed will be calcium bromide (calcium is located in group 2 so calcium bromide has a formula of CaBr2) 

so essentially we got:

HBr + Ca(OH)2 ------> CaBr2 + H2O </span>

balancing the elements: <span>

<span>2HBr(aq) + Ca(OH)2(aq) --------> CaBr2(aq) + 2H2O(l)</span></span>

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0.2 mol of hydrocarbons undergo complete combustion to give 35.2 of carbon dioxide and 14.4g of water as the only product. What
MaRussiya [10]

Answer:

\rm C_4 H_8.

Explanation:

Look up the relative atomic mass of \rm C, \rm H, and \rm O on a modern periodic table:

  • \rm C: 12.011.
  • \rm H: 1.008.
  • \rm O: 15.999.

Calculate the molecular mass of \rm CO_2 and \rm H_2O:

M(\mathrm{CO_2}) = 12.011 + 2 \times 15.999 = 44.009\; \rm g \cdot mol^{-1};

M(\mathrm{H_2O}) = 2 \times 1.008 + 15.999 = 18.015\; \rm g \cdot mol^{-1}.

Given the mass m of \rm CO_2 and \rm H_2O produced, calculate the number of moles of molecules that were produced:

\displaystyle n(\mathrm{CO_2}) = \frac{m(\mathrm{CO_2})}{M(\mathrm{CO_2})} \approx 0.80\; \rm mol;

\displaystyle n(\mathrm{H_2O}) = \frac{m(\mathrm{H_2O})}{M(\mathrm{H_2O})} \approx 0.80\; \rm mol.

Calculate the number of moles of \rm C atoms and \rm H atoms in these \rm CO_2 and \rm H_2O molecules.

  • Each \rm CO_2 molecule contains one \rm C atom. Therefore, that 0.80\; \rm mol of \rm CO_2\! contains 0.80\; \rm mol\! of \rm C\! atoms.
  • Each \rm H_2O molecule contains two \rm H atoms. Therefore, that 0.80\; \rm mol of \rm H_2O\! contains 2 \times 0.80\; \rm mol = 1.60\; \rm mol of \rm H\! atoms.

The combustion reaction here include two reactants: the hydrocarbon and \rm O_2.

As the name suggests, hydrocarbons contain only \rm C atoms and \rm H atoms. On the other hand, \rm O_2 contains only \rm O atoms.

Therefore, all the \rm C and \rm H atoms in those \rm CO_2 and \rm H_2O molecules are from the unknown hydrocarbon. (With a similar logic, all the \rm O atoms in those combustion products are from \rm O_2.)

In other words, that 0.20\; \rm mol of this unknown hydrocarbon molecules contains:

  • 0.80\; \rm mol of \rm C atoms, and
  • 1.60\; \rm mol of \rm H atoms.

Hence, each of these hydrocarbon molecules would contain (0.80\; \rm mol) / (0.20\; \rm mol) = 4 carbon atoms and (1.60\; \rm mol) / (0.20\; \rm mol) = 8 hydrogen atoms.

The molecular formula of this hydrocarbon would be \rm C_{4} H_{8}.

6 0
3 years ago
What is the molecular geometry of CO2?
Bas_tet [7]

Answer:

Tetrahedral

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7 0
2 years ago
Why can two igneous rocks that have the same minerals but different names?
photoshop1234 [79]
C. the rock may have diferrent textures 

7 0
3 years ago
Read 2 more answers
To learn more about the genetic material of plant and animal cells, where would a person look?
Agata [3.3K]
The person would look B) in the nucleus.

Hope this helps!

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6 0
3 years ago
The solubility of Cr(NO3)3⋅9H2O in water is 208 g per 100 g of water at 15 ∘C. A solution of Cr(NO3)3⋅9H2O in water at 35 ∘C is
Zinaida [17]

Answer:

102g of crystals

Explanation:

When the Cr(NO₃)₃⋅9H₂O is dissolved in water at 15°C, the maximum mass that water will dissolve in the equilibrium is 208 g per 100g of water. When you heat the water, this mass will increases.

In this problem, at 35°C the water dissolves 310g in 100g of water, as in the equilibrium at 15°C the maximum mass is 208g, the mass of crystals that will form is:

310g - 208g = <em>102g of crystals</em>

<em>-Crystals are the Cr(NO₃)₃⋅9H₂O that is not dissolved-.</em>

I hope it helps!

5 0
3 years ago
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