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2 years ago

When a bunsen burner is properly adjusted, what should the flame look like?.

Chemistry

1 answer:

DochEvi [55]2 years ago

8 0

When a bunsen burner is properly adjusted, the flame look like outer violet and inner blue colour.

<h3>What is the clolur of flame?</h3>

When a burner is properly adjusted the flame should have an outer violet oxidizing flame and an inner blue reducing flame. The temperature of blue colour is 15000 degree Celsius whereas the cool region outside the blue has 3000C temperature.

So we can conclude that When a bunsen burner is properly adjusted, the flame look like outer violet and inner blue colour.

Learn more about flame here: brainly.com/question/448102

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How much water vapor can a cubic meter of air hold at 25 degrees celcius

Thepotemich [5.8K]

I think you might find your answer here https://answers.yahoo.com/question/index?qid=20121101101721AAeZyHE

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2 years ago

Read 2 more answers

If you could place a piece of solid silver into a container of liquid silver, would it float or sink? Explain your answer.

8_murik_8 [283]

Liquid silver is less dense than solid silver, so the solid silver would sink

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2 years ago

If 10.0 g water at 0.0°C is mixed with 20.0 g of water at 30.0°C what is the final temperature of the mixture?

Bond [772]

Answer:

1.67 gradius Celcius

Explanation:

Please see the step-by-step solution in the picture attached below.

Hope this answer can help you. Have a nice day!

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2 years ago

A gas occupies 200ml at a temperature of 26 degrees Celsius and 76mmHg pressure. Find the volume at -3degree Celsius with the pr

sergey [27]

Answer:

184.62 ml

Explanation:

Let $p_1, v_1,$ and $T_1$ be the initial and $p_2, v_2,$ and $T_2$ be the final pressure, volume, and temperature of the gas respectively.

Given that the pressure remains constant, so

$p_1=p_2$ ...(i)

$v_1$ = 200 ml

$T_1= 26 ^{\circ}C = 273+26 =299$ K

$T_2= 3 ^{\circ}C = 273+3 =276$ K

From the ideal gas equation, pv=mRT

Where p is the pressure, v is the volume, T is the temperature in Kelvin, m is the mass of air in kg, R is the specific gas constant.

For the initial condition,

$p_1v_1=mRT_1 \\\\mR= \frac{p_1v_1}{T_1}\cdots(ii)$

For the final condition,

$p_2v_2=mRT_2 \\\\mR= \frac{p_2v_2}{T_2}\cdots(iii)$

Equating equation (i), and (ii)

$\frac{p_1v_1}{T_1}=\frac{p_2v_2}{T_2}$

$\frac{v_1}{T_1}=\frac{v_2}{T_2}$ [from equation (i)]

$v_2=\frac{T_2}{T_1} \times v_1$

Putting all the given values, we have

$v_2=\frac{276}{299} \times 200 = 184.62 \; ml$

Hence, the volume of the gas at 3 degrees Celsius is 184.62 ml.

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2 years ago

What type of chemical reaction will occur when iron (III) hydroxide is heated and forms new products?

Leni [432]

Answer:

Decomposition

Explanation:

A decomposition reaction is a type of reaction in which a compound is broken down into its constituent elements sometimes under the influence of heat.

When iron (III) hydroxide is heated,new products are formed according to the equation; 2Fe(OH)3 -----------> Fe2O3 + 3H2O.

This is a thermal decomposition reaction.

3 0

2 years ago