All categories

2 years ago

HELP QUICK ASSESMENT

Chemistry

2 answers:

ehidna [41]2 years ago

7 0

Answer:

MAGNESIUM

Explanation:

Serga [27]2 years ago

4 0

Answer:

Explanation:

You might be interested in

Someone please help wiht my science heheheheh

Svetllana [295]

Answer:

A, D, E

Explanation:

4 0

2 years ago

Read 2 more answers

One liter of N (g) at 2.1 bar and two liters of Ar(g) at 3.4 bar are mixed in a 4.0-L 2 flask to form an ideal-gas mixture. Calc

Vika [28.1K]

Answer:

Explanation:

From the information given:

Step 1:

Determine the partial pressure of each gas at total Volume (V) = 4.0 L

So, using:

$\text{The new partial pressure for }N_2 \ gas}$

$P_1V_1=P_2V_2$

$P_2=\dfrac{P_1V_1}{V_2} \\ \\ P_2=\dfrac{2.1 \ bar \times 1\ L}{4.0 \ L} \\ \\ P_2 = 0.525 \ bar$

$\text{The new partial pressure for }Ar \ gas}$

$P_2=\dfrac{P_1V_1}{V_2} \\ \\ P_2=\dfrac{3.4 \ bar \times 2 \ L}{4.0 \ L} \\ \\ P_2 = 1.7 \ bar$

$Total pressure= P [N_2] + P[Ar] \ \\ \\ . \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = (0.525 + 1.7)Bar \\ \\ . \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = 2.225 \ Bar$

Now, to determine the final pressure using different temperature; to also achieve this, we need to determine the initial moles of each gas.

According to Ideal gas Law.

$2.1 \ bar = 2.07 \ atm \\ \\3.4 \ bar = 3.36 \ atm$

For moles N₂:

$PV = nRT \\ \\ n = \dfrac{PV}{RT}$

$n = \dfrac{2.07 \ atm \times 1 \ L }{0.08206 \ L .atm. per. mol. K \times 304 \ K}$

$n = 0.08297 \ mol \ N_2$

For moles of Ar:

$PV = nRT \\ \\ n = \dfrac{PV}{RT}$

$n = \dfrac{3.36 \ atm \times 1 \ 2L }{0.08206 \ L .atm. per. mol. K \times 377 \ K}$

$n = 0.2172 \ mol \ Ar$

$\mathtt{total \ moles = moles \ of \ N_2 + moles \ of \ Ar}$

$=0.08297 mol + 0.2037 mol \\ = 0.2867 mol gases$

Finally;

The final pressure of the mixture is:

$PV = nRT \\ \\ P = \dfrac{nRT}{V} \\ \\ P = \dfrac{0.2867 \ mol \times 0.08206 \ L .atm/mol .K\times 377 K}{4.0 \ L}$

P = 2.217 atm

P ≅ 2.24 bar

7 0

3 years ago

Definition of emulsifier

pentagon [3]

A substance that stabilizes an emulsion, in particular a food additive used to stabilize processed foods.

3 0

2 years ago

Read 2 more answers

Look at the following diagram of the carbon cycle.

katrin2010 [14]

Answer:

The energy consumed by animals in the form of glucose is conserved because it is transformed into chemical energy as carbon dioxide is produced during respiration.

Explanation:

There's no diagram....but I kinda figured it from the description.

4 0

3 years ago

Zn+2HCl=ZnCl2+H2 How many grams of ZnCl2 will be produced from 26.0 g of Zn and 42.0 g of HCl?

irakobra [83]

53.14 grams of Zn $Cl_{2}$ will be produced from 26.0 g of Zn and 42.0 g of HCl.

Explanation:

Balanced chemical reaction:

Zn + 2 HCl ⇒ Zn $Cl_{2}$ + $H_{2}$

data given:

mass of Zn = 26 grams

mass of HCl = 42 grams

mass of Zn $Cl_{2}$ = ?

here in the reaction Zn is the limiting reagent so mass of

Zn $Cl_{2}$ formed will be determined by it.

atomic mass of zinc =65.38 grams/mole

number of moles = $\frac{mass}{atomic mass of 1 mole}$

putting the values in the above equation:

number of moles of zinc = $\frac{26}{65.38}$

number of moles of zinc = 0.39 moles

From the balanced reaction it is seen that

1 mole of Zn produced 1 mole of Zn $Cl_{2}$

0.39 moles will produce x moles of Zn $Cl_{2}$

0.39 moles of Zn $Cl_{2}$ (atomic mass of Zn = 65.38 grams/mole)

mass = atomic mass x number of moles

= 0.39 x 136.28

= 53.14 grams

53.14 grams of Zn $Cl_{2}$ is formed

5 0

2 years ago