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stira [4]
3 years ago
11

The thickness of a U.S. penny is 5.98 X 10-2 inch.

Mathematics
1 answer:
Aleksandr [31]3 years ago
4 0

Answer: 1.495*10^8\ inches

Step-by-step explanation:

For this exercise you have to remember the Product of powers property, which states that:

(a^m)(a^n)=a^{(m+n)}

Let be "x" the height in inches of a stack of 2.5*10^9 pennies.

You know that the thickness of 1 pennie is 5.98*10^{-2}\ inches, then, you can write the following proportion:

\frac{5.98*10^{-2}}{1}=\frac{x}{2.5*10^9}

Solve for "x":

(2.5*10^9)(\frac{5.98*10^{-2}}{1})=x\\\\x=14.95*10^7

To express this height in Scientific notation the decimal point must be after the first digit, so you must move it one place to the left:

x=1.495*10^8

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The window shown is the shape of a semicircle with a radius of 6 feet. The distance from F to E is 3 feet and the measure of = 4
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Answer:

The area of the glass in region BCIH is 11 to the nearest feet²

Step-by-step explanation:

* Lets explain the figure

- The window is a semicircle with center G and radius 6 feet

- There is a small semicircle with center G and radius GF

∵ GE is 6 feet and EF is 3 feet

∵ GE = GF + FE

∴ 6 = GF + 3 ⇒ subtract 3 from both sides

∴ 3 = GF

∴ The radius of the small semicircle is 3 feet

∵ m∠BGC = 45°

- The area of sector BGC is part of the area of the semicircle

∵ The area of semi-circle is 1/2 π r²

∵ The measure of the central angle of the semicircle is 180°

∵ The measure of the central angle of the sector BGC is 45°

∴ The sector = 45°/180° = 1/4 of the semi-circle

∴ The area of the sector is 1/4 the area of the semicircle

∵ The area of the semicircle = 1/2 π r²

∵ r = 6 feet

∴ The area of the semicircle = 1/2 π (6)² = 1/2 π (36) = 18 π feet²

∴ Area of the sector = 1/4 (18 π) = 4.5 π feet²

- The small sector HGI has the same central angle of the sector BGC

∴ The area of the sector HGI is 1/4 The area of the small semicircle

∵ The area of the small semicircle = 1/2 π r²

∵ r = 3 feet

∴ The area of the small semicircle = 1/2 π (3)² = 1/2 π (9) = 4.5 π feet²

∴ Area of the sector HGI= 1/4 (4.5 π) = 1.125 π feet²

- The area of the glass in region BCIH is the difference between the

  area of sector BGC and the area of the sector HGI

∴ The area of the glass in region BCIH = 4.5 π - 1.125 π ≅ 11 feet²

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3 years ago
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