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klio [65]
3 years ago
12

What is the logarithmic form for

mula1" title="2 { }^{x - 4} = 32" alt="2 { }^{x - 4} = 32" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
LiRa [457]3 years ago
6 0

Answer:

2^x-4=32\quad :\quad x=\frac{2\ln \left(6\right)}{\ln \left(2\right)}\quad \left(\mathrm{Decimal}:\quad x=5.16992\dots \right)\\\\2^x-4=32 \\\mathrm{Add\:}4\mathrm{\:to\:both\:sides}\\2^x-4+4=32+4\\\mathrm{Simplify}\\2^x=36\\\\apply exponential rule\\x\ln \left(2\right)=\ln \left(36\right)\\x\ln \left(2\right)=\ln \left(36\right)\\x=\frac{2\ln \left(6\right)}{\ln \left(2\right)}

hope it helps:)

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You didn't specify how big the festival is. so i can't find the answer.....but i will try
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5 0
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On a coordinate plane, parallelograms A B C D and E F G H are shown. Parallelogram A B C D has points (4, 2), (7, 2), (4, 6), (1
Fittoniya [83]

Answer:

The area of parallelogram ABCD is equal to the area of parallelogram EFGH.

Step-by-step explanation:

Given

Parallelogram ABCD

A = (4,2)

B = (7,2)

C =(4,6)

D = (1,6)

Parallelogram EFGH

E =(-2,2)

F = (-5,2)

G = (-6,6)

H = (-3,6)

Required

Compare the areas of both parallelograms

The area of a parallelogram is:

Area =Base * Height

So: To do this, we plot ABCD and EFGH on a grid, then we measure the base and the height of both.

See attachment 1 for ABCD

In (1), we have:

Base = 3\ units

Height = 4\ units

So, the area is:

A_1 = 3 * 4

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See attachment 2 for EFGH

In (2), we have:

Base = 3\ units

Height = 4\ units

So, the area is:

A_2 = 3 * 4

A_2 = 12

<em>By comparison, they both have the same areas</em>

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A dilation of 2 was performed (:
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