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2 years ago

describe how axioms about addition in particular could be helpful in developing theorems about multiplication.

1 answer:

8 0

The axioms in addition help in developing theorems about multiplication because multiplication, in simple terms, repeated addition.
As an example,
This addition operation
3 + 3 + 3 + 3 = 12
can be expressed as a multiplication operation
3 x 4 = 12

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Write the inequality given in the diagram below

11111nata11111 [884]

Answer:

x ≥ - 1

Step-by-step explanation:

the solid circle above - 1 on the number line indicates that x can equal - 1

the arrow points right indicating x is greater than or equal to - 1 , that is

x ≥ - 1

4 0

1 year ago

A. f(x) = l-2xl - 3 Domain: {1, 2, 3} Find the range

gizmo_the_mogwai [7]

Hello there!

We are given the function:

$\displaystyle \large{ f(x) = | - 2x| - 3} \\$

To find the range, we know that domain is the set of all x-values and also called 'input' while range is the set of all y-values and also called 'output'.

Basic Function - you add the input, you get the output. You add x-value in a function, you get y-value. You add domain, you get range.

So, we substitute x = 1,2 and 3 in the function.

x = 1

$\displaystyle \large{ f(1) = | - 2(1)| - 3} \\ \displaystyle \large{ f(1) = | - 2| - 3} \\$

Recall that any numbers in absolute value are always positive.

$\displaystyle \large{ f(1) = 2 - 3} \\ \displaystyle \large{ f(1) = - 1} \\$

x = 2

$\displaystyle \large{ f(2) = | - 2(2)| - 3} \\ \displaystyle \large{ f(2) = | - 4 | - 3} \\ \displaystyle \large{ f(2) = 4 - 3} \\ \displaystyle \large{ f(2) = 1}$

x = 3

$\displaystyle \large{ f(3) = | - 2(3)| - 3} \\ \displaystyle \large{ f(3) = | - 6| - 3} \\ \displaystyle \large{ f(3) = 6 - 3} \\ \displaystyle \large{ f(3) = 3}$

Therefore, Range: {-1,1,3}

Let me know if you have any questions!

Topic: Absolute Value Function / Modulus Function

6 0

2 years ago

Julie and her brother go to Atlanta to ride the SkyView Ferris wheel. It measures 200 feet in diameter.

Law Incorporation [45]

Answer:

Question 1: A)we need to use the CIRCUMFERENCE.

B) Circumference of a Circle = 2 π R

c)The distance traveled in 1 rotation = 628 ft

2(a)AREA of a CIRCLE = π R²

(b)Area the wheel takes up is 31,400 sq ft

Step-by-step explanation:

Question 1:

Diameter = 200 ft

Now,as Diameter = 2 x Radius

So, R = D/2 =200/2 = 100 ft

A) Distance around the wheel = The length of the boundary of the wheel.

So, we need to use the CIRCUMFERENCE.

B) Circumference of a Circle = 2 π R

Here R = Radius and use π = 3.14

C) The distance traveled in 1 rotation = 1 completer length of boundary

Now, Circumference = 2 π R = 2 x (3.14) x (100 ft) = 628 ft

Question 2:

A) Space the Ferris Wheel takes up = Area of the wheel

AREA of a CIRCLE = π R²

B) AREA of a CIRCLE = π R²

= (3.14) (100 ft ) (100 ft) = 31,400 sq ft

So, the area the wheel takes us is 31,400 sq ft

3 0

2 years ago

Which of exercises 14-19 could you solve mentally

hammer [34]

where are 14-19? picture?

3 0

2 years ago

Read 2 more answers

What is the number in scientific notation? 0.000013

12345 [234]

Answer:

1.3 x 10^-5

Step-by-step explanation:

8 0

2 years ago