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ValentinkaMS [17]
4 years ago
11

Calculate the probability for the following situation, then select the correct answer:You are tossing a coin, then rolling a die

, then drawing a card from a deck of cards. What is the probability that you will get: a head AND an odd number on the die AND a card less than 10 (assume the ace is equal to 1) from the deck?
Mathematics
2 answers:
n200080 [17]4 years ago
5 0

Answer:

9/52

Step-by-step explanation:

This is a case of multiple events happening at the same time, so we need to find the probability of each event and multiply them together.

Formula for finding probability is as follow:

<em>P(E) = Number of Favorable Outcomes / Number of Total Outcomes</em>

Probability of Heads:

Favorable Outcomes = 1 (Heads)

Total Outcomes = 2 (Heads, Tails)

P(H) = 1/2

Probability of Odd Number:

*<em>Assuming six sided unbiased die</em>

Favorable Outcome = 3 (1, 3, 5)

Total Outcomes = 6 (1, 2, 3, 4, 5)

P(Odd) = 3/6 or 1/2

Probability of Card Less than 10:

*<em>Assuming a deck of  52 cards </em>

Favorable Outcomes = 36 (Ace, 2, 3, 4, 5, 6, 7, 8, 9  times 4)

Total Outcomes = 52 (Ace, 2, 3 ,4 ,5 ,6 ,7 ,8 ,9, 10, J, Q, K times 4)

P(<10) = 36/52 or 9/13

Probability of All Events Occurring:

P(E) = P(H) x P(Odd) x P(<10)

P(E) = 1/2 x 1/2 x 9/13

P(E) = 9/52  --------------------- Answer

AlekseyPX4 years ago
5 0

Answer:

9/52

Step-by-step explanation:

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<h2>Answer:</h2>

1. Between April 1 and May 1, Bob's price incrdased by <u>$0.50 or 15%</u>.

2. Between May 1 and June 1, Bob's price decreased by <u>$0.50 or 13%</u>.

3. Suppose that atgas station across the street, prices are always 20% higher than Bob's. In absolute dollar terms, the difference between Bob's prices and the prices across the street is <u>$0.1 more expensive</u> when gas costs $3.85 than when gas costs $3.35.

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<h3>1. Between April 1 and May 1, Bob's price incrdased by...</h3>

<em>Take the difference of the prices to find an absolute value:</em>

$3.85 - $3.35= $0.50.

<em>Use the following formula to find the relative value:</em>

C= |Original value - New value|/ Original value

C=\frac{|OV-NV|}{OV}=\frac{|3.35-3.85|}{3.35}  =0.15=15%.

<h3>2. Between May 1 and June 1, Bob's price decreased by...</h3>

<em>Take the difference of the prices to find an absolute value:</em>

$3.85 - $3.35= $0.50.

<em>Use the following formula to find the relative value:</em>

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<h3>3. Suppose that atgas station across the street, prices are always 20% higher than Bob's. In absolute dollar terms, the difference between Bob's prices and the prices across the street is (blank) when gas costs $3.85 than when gas costs $3.35.</h3>

<em>In this question we are looking for the difference of a difference. </em>

<em>If the proces across the street are always 20% higher, to find how much the gallon costs just multiply the price by 1.20, to increase 0.2 or 20%:</em>

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<em>Now, to see how much expensive this price is compared to Bob's, take de difference between the prices:</em>

$4.62 - $3.85= $0.77.

<em>Do the same to find the difference between the gas prices when the price is $3.35.</em>

$3.35 * 1.20= $4.02.

$4.02 - $3.35= $0.67.

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$0.77 - $0.67= $0.1.

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