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VARVARA [1.3K]
3 years ago
10

Please help me!

Mathematics
1 answer:
mojhsa [17]3 years ago
7 0

Answer:

1B

2A

3. x>5+sqrt19 or x<5-sqrt19

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Please please help! I'm stuck on this
Phantasy [73]

Answer:

A'(-4 , 10)

B'(-4, 12)

C'(0, 12)

D'(0, 10)

Step-by-step explanation:

Given in the question are 4 coordinates of Quadrilateral ABCD

A(−2, 2)

B(−2, 4)

C(2, 4)

D(2, 2)

The rule is (x − 2, y + 8), that means

the translation is 2 units to the left and 8 units up

Applying the rule of the translation

Step1

A(-2, 2) = A'(-2-2 , 2+8) = A'(-4 , 10)

Step 2

B(−2, 4) = B'(-2-2 , 4+8) = B'(-4, 12)

Step 3

C(2, 4) = C'(2-2 , 4+8) = C'(0, 12)

Step 4

D(2, 2) =  D'(2-2 , 2+8) = D'(0, 10)

Describe what characteristics you would find if the corresponding vertices were connected with line segments.

If point A was connected to point A', point B was connected to point B',point C was connected to point C', point D was connected to point D' then all of these line will be parallel to each other, since they were all transformed by the same amount (x-2, y+8).

5 0
3 years ago
How are weather balloons and weather satellites similar?
Ymorist [56]
The answer is A. Both collect weather data.

Answer B is false, Balloons generally deconstruct, Satellites do not as they are meant to orbit way past the stratosphere.
Answer C is false, Only satellites can go past the exosphere.
D. Neither of them have any sort of impact on the weather.


7 0
4 years ago
Read 2 more answers
If you flip a coin 4 times, how many times it is most likely to land with heads up?
TEA [102]
If you flip it at a certan hight than all 4
4 0
3 years ago
I don't know what to write! Help me please​
Andrews [41]
Sorry, can not see the full picture, try uploading the full image of the question.
3 0
4 years ago
3x^2 – 8x + 5 = 5x^2
Ghella [55]

Answer:

Step-by-step explanation:

3x^2 -8x +5 = 5x^2\\\\5x^2 - 3x^2 + 8x -5 =0\\\\2x^2 +8x -5 = 0\\\\

a = 2, b = 8, c = -5

x = \frac{-b \pm \sqrt{b^2 -4ac} }{2a}\\\\x = \frac{-8 \pm \sqrt{8^2 - ( 4 \times 2 \times (-5))} }{2 \times 2}\\\\x = \frac{-8 \pm \sqrt{64 +40} }{4}\\\\x = \frac{-8 + \sqrt{64 +40} }{4} \ , \ x = \frac{-8 - \sqrt{64 +40} }{4}\\\\x = \frac{-8 + \sqrt{104} }{4} \ , \ x = \frac{-8 - \sqrt{104} }{4}\\\\x = \frac{-8 + \sqrt{4 \times 26} }{4} \ , \ x = \frac{-8 - \sqrt{4 \times 26} }{4}\\\\x = \frac{-8 +2 \sqrt{26} }{4} \ , \ x = \frac{-8 - 2\sqrt{26} }{4}\\\\

x = \frac{-4 + \sqrt{26} }{2} \ , \ x = \frac{-4 - \sqrt{26} }{2}

8 0
3 years ago
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