You are correct. For any polygon, the sum of the exterior angles is 360 degrees. You have the correct equation which leads to the correct answer. Nice work on that.

7 0

3 years ago

(5 points) An urn contains two blue balls denoted by B1 and B2, and three white balls denoted by W1, W2 and W3. One ball is draw

never [62]

Answer:

The probability of the event that first ball that is drawn is blue is $\frac 25$ .

Step-by-step explanation:

Probability:

If S is is an sample space in which all outcomes are equally likely and E is an event in S, then the probability of E,denoted P(E) is

$P(E)=\frac{\textrm{The number of outcomes E}}{\textrm{The total number outcomes of S}}$

Given that,

An urn contains two balls B₁ and B₂ which are blue in color and W₁,W₂ and W₃ which are white in color.

Total number of ball =(2+3) =5

The number ways of selection 2 ball out of 5 ball is

=5²

=25

Total outcomes = 25

List of all outcomes in the event that the first ball that is drawn is blue are

B₁B₁ , B₁B₂ , B₁W₁ , B₁W₂ , B₁W₃ , B₂B₁ , B₂B₂ , B₂W₁ , B₂W₂ , B₂W₃

The number of event that the first ball that is drawn is blue is

=10.

The probability of the event that first ball that is drawn is blue is

$=\frac{10}{25}$

$=\frac25$

3 0

4 years ago