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Brilliant_brown [7]
2 years ago
10

Solve the inequality.2(4+2x)>5х+5 x<-2 x>-2х<3x>3​

Mathematics
1 answer:
olga_2 [115]2 years ago
4 0

Answer:

x<3

Step-by-step explanation:

You might be interested in
Algebra
vladimir2022 [97]
(2x + 3y = 12) x (-2)
(4x - 3y = 6) x 1

-4x - 6y = -24
4x - 3y = 6

You can cancel out the x values by adding the two equations together. 
(-4x + 4x) + (-6y - 3y) = (-24 + 6)
-9y = -18
y = 2

Solve for x now...
4x - 3(2) = 6
4x - 6 = 6
4x = 12
x = 3

Check... (x = 3, y = 2)
2(3) + 3(2) = 12 
6 + 6 = 12
12 = 12 <- this works! 

4(3) - 3(2) = 6
12 - 6 = 6
6 = 6 <- this works!
5 0
2 years ago
Read 2 more answers
Ben and irie made a secret code. they wrote some numbers of the code so they could remember the pattern. what should the next nu
stiks02 [169]
Well what was the pattern they had 

4 0
3 years ago
Which of the following inequalities is correct?
Mariana [72]

Is the answer -5 > 0?

7 0
2 years ago
3y-4x=3 find the rate of change for each function above Which function has the greatest rate of change?does any pair of function
pishuonlain [190]

Answer:

4/3

Step-by-step explanation:

Sounds as though this problem presented several rates of change, but you have shared only one:  3y - 4x = 3.  If we take x to be the independent variable, then 3y = 4x + 3, and y = (4/3)x + 1.  The rate of change of this function (the rate of change of y with respect to x) is therefore 4/3.

7 0
3 years ago
Question 2:
Helga [31]

Answer:

15mins

Step-by-step explanation:

Given that he worked out a total of 360mins, and jogged 45mins/day:

Jog \ Time=Total \ Time- Bike \ Time\\=360-(45\times6)\\=90min

Therefore, Allen jogged a total of 90mins in the past one week. To calculate the time jogged each day, we divide the total jog time by number of days jogged:

t_d=Total \Time/(No \of \ Days)\\=90/6\\=15mins

Allen jogged 15mins per day.

6 0
3 years ago
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