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3 years ago

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A frozen yogurt shop conducted a survey in which it asked every fourth customer for his or her favorite flavor. Most of the cust

omers surveyed preferred vanilla yogurt, so the shop concluded that the customers' favorite flavor is vanilla. Is this a valid conclusion?

1 answer:

Mrrafil [7]3 years ago

6 0

Answer:

Step-by-step explanation:

yes

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1. The price of gas has increased over time due to inflation and other factors.

lorasvet [3.4K]

Answer:

Step-by-step explanation:

The equation representing the price of gas for the years after 2000 is expressed as

y = 1.26(1.10)^x

Where x = 0, 2, 4, 6, 8, and 10 represent these years : 2000, 2002, 2004, 2006, 2008, and 2010, the table would be

1) x = 0(2000)

y = 1.26(1.10)^0

y = 1.3

2) x = 2(2002)

y = 1.26(1.10)^2

y = 1.5

3) x = 4(2004)

y = 1.26(1.10)^4

y = 1.8

4) x = 6(2004)

y = 1.26(1.10)^6

y = 2.2

5) x = 8(2006)

y = 1.26(1.10)^8

y = 2.7

6) x = 10(2008)

y = 1.26(1.10)^10

y = 3.3

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3 years ago

If f(1) = 160 and f(n + 1) = –2f(n), what is f(4)?

sashaice [31]

Hello,

f(1)=160
f(2)=160*(-2)
f(3)=160*(-2)²
f(4)=160*(-2)^3=-1280

f(n)=160*(-2)^(n-1)

8 0

3 years ago

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What is the Y 2(7y−1)=40

MissTica

Answer:

3

Step-by-step explanation:

2(7y−1)=40

14y-2=40

14y=40+2

14y=42

y=3

please mark as brainliest

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3 years ago

Read 2 more answers

Need help with 10 and 11 can’t figure it out

Artyom0805 [142]

Wish I could help on so sorry

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3 years ago

A couple book a cruise to Alaska that promises to refund 100 per day of rain on the seven day cruise up to a maximum of 300. The

zubka84 [21]

Answer:

the variance of the refund payment to the couple = 9463.394

Step-by-step explanation:

Given that :

A couple book a cruise to Alaska that promises to refund 100 per day of rain on the seven day cruise up to a maximum of 300.

It is possible that the couple won't be able to refund up 100 per day or more than 100 per day.

SO; let assume that the refund payment happens to be 0, 100,200, 300

Let X be the total refund payment on the seven day cruise.

We can say X = 0, if there is no rain on all 7 days.

$P(X = 0) = _nC_x * P^x * (1 - P)n-x$

$P(X = 0) = _7C_o * 0.2^0 * (1-0.2)^{7-0$

$P(X = 0) =1 * 1* (1-0.2)^{7$

$P(X = 0) =(0.8)^{7$

$P(X = 0) =0.2097152$

If it rains on any one day; then X = 100

$P(X = 100) = _nC_x * P^x * (1 - P)n-x$

$P(X = 100) = _7C_1 * 0.2^1 * (1-0.2)^{7-1$

$P(X = 0) =7 * 0.2* (1-0.2)^{6$

$P(X = 100) =7* 0.2* (0.8)^{6$

$P(X = 100) =0.3670016$

if it rains on any two day ; then X = 200

$P(X = 200) = _nC_x * P^x * (1 - P)n-x$

$P(X = 200) = _7C_2 * 0.2^2 * (1-0.2)^{7-2$

$P(X = 200) = 21 * 0.2^2 * (0.8)^{5$

$P(X = 200) = 0.2752512$

if it rains on any three day or more than that ; then X = 300

$P(X \ge 300) = 1 - P(X < 300) \\ \\ P(X \ge 300) = 1 - [P(X = 0) + P(X = 100) + P(X = 200)] \\ \\ P(X \ge 300) = 1 - [0.2097152 + 0.3670016 + 0.2752512] \\ \\ P(X \ge 300) = 0.148032$

Now; we have our probability distribution function as:

P(X = 0) = 0.2097152

P(X = 100) = 0.3670016

P(X = 200) = 0.2752512

P(X = 300) = 0.148032

In order to determine the variance of the refund payment to the couple; we use the formula:

variance of the refund payment to the couple $[Var X] =E [X^2] - (E [X])^2$

where;

$E[X^2] = \sum x^2 \times p \\ \\ E[X^2] = 0^2 * 0.2097152 + 100^2 * 0.3670016 + 200^2 * 0.2752512 + 300^2 * 0.148032 \\ \\ E[X^2] = 0 + 3670.016 + 11010.048+ 13322.88 \\ \\ E[X^2] =28002.944$

$(E [X]) = \sum x * p\\ \\ (E [X]) = 0 * 0.2097152 + 100 * 0.3670016 + 200 * 0.2752512 + 300 * 0.148032 \\ \\ (E [X]) = 0 + 36.70016 + 55.05024 + 44.4096\\ \\ (E [X]) = 136.16 \\ \\ (E [X])^2 = 136.16^2 \\ \\ (E [X])^2 = 18539.55$

NOW;

the variance of the refund payment to the couple = 28002.944 - 18539.55

the variance of the refund payment to the couple = 9463.394

7 0

3 years ago