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lana [24]
3 years ago
7

When the center line is one solid yellow line and one broken yellow line, who may cross the line to pass?

Mathematics
1 answer:
Serjik [45]3 years ago
3 0

Answer:

the side with the yellow broken line

Step-by-step explanation:

Solid yellow line: No passing when solid yellow line is on your side. Double solid lines: No vehicle may pass. Broken yellow line: May pass if movement can be made in safely. Many roads have two or more lanes going in your direction.

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Two angles in a triangle measure (2.3x+25)° and (5.8x+11)°. what is the value of x if the two angles are congruent to one anothe
Anton [14]

Answer:

The answer is D. x= 4

Step-by-step explanation:

The angles are congruent so

2.3x +25 = 5.8x + 11

2.3x - 5.8x = 11 - 25

-3.5x = -14

x = 14/3.5

x = 4.

5 0
3 years ago
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Which of the following functions is graphed below.
Valentin [98]

Answer: Option A

y=\left \{ {{x^2 +2;\ \ x

Step-by-step explanation:

In the graph we have a piecewise function composed of a parabola and a line.

The parabola has the vertex in the point (0, 2) and cuts the y-axis in y = 2.

The equation of this parabola is y = x ^ 2 +2

Then we have an equation liney = -x + 2


Note that the interval in which the parabola is defined is from -∞ to x = 1. Note that the parabola does not include the point x = 1 because it is marked with an empty circle " о ."

(this is x< 1)

Then the equation of the line goes from x = 1 to ∞ . In this case, the line includes x = 1 because the point at the end of the line is represented by a full circle .

(this is x\geq 1)

Then the function is:

y=\left \{ {{x^2 +2;\ \ x

7 0
3 years ago
9.
Yanka [14]
I’m not sure if I get the question, but the second one would be a fact and the others are all statements. I hope this helps :)
5 0
3 years ago
X^2 +18 =15 could anyone help me with this?
stiv31 [10]

Answer:

x = i√3, -i√3

Step-by-step explanation:

Simply take the root of both sides, then solve.

8 0
3 years ago
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Which of the following algebraic equations is equivalent to ?
ipn [44]

If it's mutiple choice can I see the options :) would make this easier

8 0
3 years ago
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