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STatiana [176]
3 years ago
8

A new car costs the purchase price, plus a 7.5% tax. The cost of the car can be written as x + 0.075x. Write an equivalent expre

ssion to show the cost of the car.
Mathematics
1 answer:
mr Goodwill [35]3 years ago
3 0

Answer:

Step-by-step explanation:

The cost = x * (1 + 0.075) = x * 1.075 = 1.075*x

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Find the midpoint of the segment with the following endpoints.<br> (7, -2) (1, -10)
dem82 [27]

Answer:

<h2>(4, -6)</h2>

Step-by-step explanation:

The formula of a midpoint of the segment AB:

M_{AB}\left(\dfrac{x_A+x_B}{2};\ \dfrac{y_A+y_B}{2}\right)

We have A(7, -2) and B(1, -10). Substitute:

M_{AB}\left(\dfrac{7+1}{2};\ \dfrac{-2+(-10)}{2}\right)\\\\M_{AB}\left(\dfrac{8}{2};\ \dfrac{-12}{2}\right)\\\\M_{AB}(4;\ -6)

8 0
3 years ago
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How do you write 1 and 1/4
S_A_V [24]
If you mean as an improper fraction, you multiply the whole number by the denominator then add the numerator to get 5/4. If you mean to a decimal, then 1.25.
6 0
3 years ago
Read 2 more answers
Find the missing side lengths.
Zigmanuir [339]

Answer:

x is 18, and y is 9 √ 3

Step-by-step explanation:

Since this is a right triangle that contains a 30 degree angle, we know this is a special right triangle, and the missing angle is 60 degrees since a triangle is 180 degrees, and 180 - 90 - 30 = 60.

The relationship is listed below:

The side opposite of the 30 degrees can be represented as a variable, say "p", and the hypotenuse which is x in your question is twice this. The side opposite of the 60 degree angle is x + √3

So x is 18, and y is 9√3

6 0
3 years ago
Which of the following expressions is equal to 5-2m?
fiasKO [112]
The answer would be A. Make sure you also use BEDMAAS, and take care of the brackets first
6 0
3 years ago
Let w(s,t)=f(u(s,t),v(s,t)) where u(1,0)=−6,∂u∂s(1,0)=5,∂u∂1(1,0)=7 v(1,0)=−8,∂v∂s(1,0)=−8,∂v∂t(1,0)=6 ∂f∂u(−6,−8)=−1,∂f∂v(−6,−8
Blababa [14]
w(s,t)=f(u(s,t),v(s,t))

From the given set of conditions, it's likely that you are asked to find the values of \dfrac{\partial w}{\partial s} and \dfrac{\partial w}{\partial t} at the point (s,t)=(1,0).

By the chain rule, the partial derivative with respect to s is

\dfrac{\partial w}{\partial s}=\dfrac{\partial f}{\partial u}\dfrac{\partial u}{\partial s}+\dfrac{\partial f}{\partial v}\dfrac{\partial v}{\partial s}

and so at the point (1,0), we have

\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial &#10;u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial s}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial &#10;v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial s}\bigg|_{(s,t)=(1,0)}
\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=(-1)(5)+(2)(-8)=-21

Similarly, the partial derivative with respect to t would be found via

\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial &#10;u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial t}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial &#10;v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial t}\bigg|_{(s,t)=(1,0)}
\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=(-1)(7)+(2)(6)=5
6 0
4 years ago
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