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kicyunya [14]
3 years ago
10

If line t is perpendicular to both line l and line m, then ∠1 and ∠2 are both ____ angles. Question acute right obtuse complemen

tary

Mathematics
2 answers:
ella [17]3 years ago
8 0
They are both right angles. 
Masja [62]3 years ago
8 0

Answer:

∠1 and ∠2 both are right angles.

Step-by-step explanation:

Given that if line t is perpendicular to both line l and line m, then

we have to find about the angle ∠1 and ∠2

As given line l is perpendicular to both line l and line m,

Therefore the point at which the ;line intersect the two lines l and m at 90° i.e

∠1 and ∠2 both angles are formed at the intersection points of line t with l and m.

Hence, ∠1 and ∠2 both are right angles.

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Which shows all the critical points for the inequality x2-4/x2-5x+6<0
Hoochie [10]

Answer:

x = ±2, 3 are the critical points of the given inequality.

Step-by-step explanation:

The given inequality is \frac{(x^{2}- 4)}{x^{2}-5x+6}

To find the critical points we will equate the numerator and denominator of the inequality to zero.

For numerator,

x^{2}-4=0

(x - 2)(x + 2) = 0

x = ±2

For denominator,

x² - 5x + 6 = 0

x² - 3x -2x + 6 = 0

x(x - 3) -2(x - 3) = 0

(x - 3)(x - 2) = 0

x = 2, 3

Therefore, critical points of the inequality are x = ±2, 3 where the sign of the inequality will change.

7 0
3 years ago
3 people can deliver 1000 letters in 30 minutes.
Studentka2010 [4]

Answer:  It would take 1 hour and 30 minutes for one people do it.

If 5 people do it would take less time. If there are 5 people delivering the letters it would take them 12 minutes ti deliver all 1,000 letters.

6 0
3 years ago
Please answer this problem!
harina [27]

Answer:

a. volume= 784 is the answer

8 0
2 years ago
Researchers studying two populations of wolves conducted a two-sample tt-test for the difference in means to investigate whether
Stells [14]

Answer:

A. Assuming that the mean weights of wolves in the populations are equal, the probability of obtaining a test statistic that is greater than 2.771 or less than −2.771 is 0.01.

Step-by-step explanation:

5 0
3 years ago
What is the 6th term of the geometric sequence where a1 = -4096 and a4 = 64?
Akimi4 [234]
\bf \begin{array}{llccll}
term&value\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
a_1&-4096\\
a_2&-4096r\\
a_3&-4096rr\\
a_4&-4096rrr\\
&-4096r^3\\
&64
\end{array}\implies -4096r^3=64
\\\\\\
r^3=\cfrac{64}{-4096}\implies r^3=-\cfrac{1}{64}\implies r=\sqrt[3]{-\cfrac{1}{64}}
\\\\\\
r=\cfrac{\sqrt[3]{-1}}{\sqrt[3]{64}}\implies \boxed{r=\cfrac{-1}{4}}\\\\
-------------------------------

\bf n^{th}\textit{ term of a geometric sequence}\\\\
a_n=a_1\cdot r^{n-1}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
r=-\frac{1}{4}\\
a_1=-4096\\
n=6
\end{cases}
\\\\\\
a_6=-4096\left( -\frac{1}{4} \right)^{6-1}\implies a_6=-4^6\left( -\frac{1}{4} \right)^5
4 0
3 years ago
Read 2 more answers
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