Try using 2 and 5.. 2x{[(12-3)x3]+(5x6)-8}=98
Answer:
X2+8X+6=0
We add all the numbers together, and all the variables
X^2+8X+6=0
a = 1; b = 8; c = +6;
Δ = b2-4ac
Δ = 82-4·1·6
Δ = 40
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
X1=−b−Δ√2aX2=−b+Δ√2a
The end solution:
Δ−−√=40−−√=4∗10−−−−−√=4√∗10−−√=210−−√
X1=−b−Δ√2a=−(8)−210√2∗1=−8−210√2
X2=−b+Δ√2a=−(8)+210√2∗1=−8+210√2
Step-by-step explanation:
Answer:
x
Step-by-step explanation:
yzbsksmssnzndnnkskksksmms
Answer:
X=-7
Step-by-step explanation:
When "subtracting" negatives it's basically like adding them together, but the numbers get farther away from 0 going left... The equation could look like
-7 - 2 = -9 <em>or </em>-7 + (-2) = -9 :)
