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Lapatulllka [165]
3 years ago
14

Help! Asap ASAP!!!!!!

Mathematics
1 answer:
Katen [24]3 years ago
7 0

I believe there is no way to solve it. You could just put it in friction form of

n2+10n+18

——————

n+5

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Can someone explain the answer to this and how to work it
9966 [12]
Your answer is 3/5, the picture below shows how sin cos tan work!

5 0
3 years ago
13.
brilliants [131]

Answer:

The answer to your question is: midsegment = 35 units

Step-by-step explanation:

Use the Thales' theorem

                          \frac{3x + 55}{6x + 5} = \frac{86}{43} \\

                          43( 3x + 55) = 86( 6x + 5)

                          129x + 2365 = 516x + 430

                          129x - 516x = 430 - 2365

                          -387x = -1935

                           x = -1935 / -387

                           x = 5

Midpoint length = 6(5) + 5

                           = 30 + 5

                          = 35 units

8 0
3 years ago
Plz help !!!!!! whoever answers correct and first gets brainliest
vfiekz [6]

Answer:

B) 747.7 \ yd^2

Step-by-step explanation:

Given:

Height of cylinder (h) = 10 yd

Diameter of cylinder (d) = 14 yd

We need to find the surface area of the cylinder.

Solution:

First we will find the radius of the cylinder.

Radius is half of the diameter.

radius (r) = \frac{14}{2} = 7\ yd

Now we know that;

Surface area of cylinder is equal to 2 times π times radius(r) times sum of radius (r) and height (h).

Framing in equation form we get;

Surface area of cylinder = 2\pi r(h+r)

Substituting the given values we get;

Surface area of cylinder = 2\pi \times 7(7+10)= 2\pi \times7\times 17 = 747.699 \yd^2

Rounding to nearest tenth we get;

Surface area of cylinder = 747.7 \ yd^2

Hence the surface Area of cylinder is 747.7 \ yd^2.

3 0
3 years ago
What is 2y+4x =10 in y=mx+b
Dimas [21]

Answer:

The answer should be y = -2x + 5

Step-by-step explanation:

Subtract 4x to move it to the other side.

(2y = -4x + 10)

Then you divide both sides by 2 to get y by itself.

4 0
3 years ago
Consider the graph of the cosine function shown below.
nata0808 [166]

Answer:

a. Amplitude: 4

Period: 1

b. The maximum values occur at \theta=0,1,2

The minimum values occur at \theta=\frac{1}{2},\frac{3}{2}

The zeros occur at \theta=\frac{1}{4},\frac{3}{4},\frac{5}{4},\frac{7}{4}

Step-by-step explanation:

We can see from the graph that;

-4\le f(x) \le 4.

This implies that;

|A|=4.

The amplitude is 4.

The function also completed one full cycle on the interval [0,1]

The period is

T=|1-0|=1

The maximum values occur at \theta=0,1,2

The minimum values occur at \theta=\frac{1}{2},\frac{3}{2}

The zeros occur at \theta=\frac{1}{4},\frac{3}{4},\frac{5}{4},\frac{7}{4}

This is where the graph intersected the x-axis.

7 0
3 years ago
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