the first term of an arithmetic sequence is 8, the last term id 56 and the sum is 416. find the number of terms

Mathematics

1 answer:

Morgarella [4.7K]2 years ago

7 0

Answer:

Step-by-step explanation:

first term (a) = 8

last term ( ) = 56

sum (S) = 416

number of terms (n) = ?

equation

S = n/2 (a+)

416 = n/2 (8+56)

416 = n/2 (64)

416 = 32n

n = 416/32 = 13

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