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Rashid [163]
4 years ago
8

How many C-13 atoms are present, on average, in a 2.1000×104-atom sample of carbon?

Chemistry
1 answer:
Tasya [4]4 years ago
3 0
C-13 or Carbon-13 is an isotope of carbon that has a relative abundance of 1.109%. The other isotopes of carbon are C-12 and C-14. We use this percentage to multiply to the total atoms of carbon. The solution is as follows:

2.1×10⁴ atoms * 1.109/100 = 232.89 atoms of C-13
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p=mv

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v = velocity of the object

In the given question, we are given that a child of mass 21.0 kg is carrying a gallon of milk having mass 2.25 kg and running with a velocity of 2.5 m/s. Hence, the momentum by both milk and child will be:

p=(m_{child}+m_{milk})v     ....(1)

Given:

m_{child}=21.0kg\\m_{milk}=2.25kg\\v=2.5m/s\\p=?kg.m/s

Putting values in equation 1, we get:

p=(21+2.25)kg\times 2.5m/s=58.125kg.m/s

Hence, the momentum of the child and milk together is 58.125 kg.m/s

7 0
4 years ago
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