Answer:
0.0000098 should be the answer
Explanation:
Answer:
The empirical formula of the compound C₃H₆N₂ is C₃H₆N₂
Explanation:
The empirical formula of a compound is the formula of the compound given in the (smallest) whole number ratio of the elements of the compound
The empirical formula of S₂O₂ is SO
The empirical formula of C₃H₆O₃ is CH₂O
The given compound's molecular formula is C₃H₆N₂
The smallest whole number ratio of of the elements of the compound is 3:6:2, therefore, the empirical formula of the compound C₃H₆N₂ is C₃H₆N₂.
Answer:
i think mix im um 1s 6f 4d is correct answer
The answer is C good luck
Answer:
The answer to your question is 0.64 M
Explanation:
Data
Sucrose C₁₂H₂₂O₁₁ mass = 7.633 g
volume = 25 ml
Molarity = ?
Process
1.- Calculate the molar weight of Sucrose
C₁₂H₂₂O₁₁ = (12 x 12) +(22 x 1) + (11 x 16)
= 144 + 22 + 176
= 342 g
2.- Calculate the moles of sucrose
342 g ------------------ 1 mol
7.633 g --------------- x
x = (7.633 x 1) / 342
x = 0.0223 moles
3.- Calculate the molarity
Molarity = moles / volume (L)
Molarity = 0.0223 / 0.035
Molarity = 0.64
