Question

35S has a half-life of 88 days. You start with 128 micrograms of 3Ss. How much 35s is left after 264 days? O a. 32 micrograms b.8 micrograms O c. 64 micrograms O d. 16 micrograms O e. 4 micrograms

Answer 1

Answer:

Option d, Amount left = 16 μg

Explanation:

Half life = 88 days

Initial concentration = 128 μg

$No.\ of\ half\ life=\frac{Total\ days}{t_{1/2}}$

$No.\ of\ half\ life=\frac{264}{88} = 3$

Amount of material left after n half life = $\frac{Amount\ of\ starting\ material}{2^n}$

Where, n = No. of half life

Amount of material left = $\frac{128}{2^3}$

                                       = $\frac{128}{8} = 16$μg

SO, option d is correct