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charle [14.2K]
4 years ago
6

35S has a half-life of 88 days. You start with 128 micrograms of 3Ss. How much 35s is left after 264 days? O a. 32 micrograms b.

8 micrograms O c. 64 micrograms O d. 16 micrograms O e. 4 micrograms
Chemistry
1 answer:
pochemuha4 years ago
7 0

Answer:

Option d, Amount left = 16 μg

Explanation:

Half life = 88 days

Initial concentration = 128 μg

No.\ of\ half\ life=\frac{Total\ days}{t_{1/2}}

No.\ of\ half\ life=\frac{264}{88} = 3

Amount of material left after n half life = \frac{Amount\ of\ starting\ material}{2^n}

Where, n = No. of half life

Amount of material left = \frac{128}{2^3}

                                       = \frac{128}{8} = 16μg

SO, option d is correct

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