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Mamont248 [21]
2 years ago
7

Which spectroscopic tool would be best for distinguishing a sample of 1,2-dichloropropane from 1,2-dibromopropane?

Chemistry
1 answer:
german2 years ago
4 0

The NMR spectroscopy will be used for distinguishing a sample of 1,2-dichloropropane from 1,2-dibromopropane.

A spectroscopic method for observing the local magnetic fields surrounding atomic nuclei seems to be nuclear magnetic resonance spectroscopy, also referred to as magnetic resonance spectroscopy as well as NMR spectroscopy.

The identification and study of organic molecules benefit greatly from nuclear magnetic resonance (NMR) spectroscopy. This type of spectroscopy has a straightforward underlying theory. Numerous atom types' nuclei behave like small magnets and frequently align themselves in magnetic fields.

Therefore, the NMR spectroscopy will be used for distinguishing a sample of 1,2-dichloropropane from 1,2-dibromopropane.

To know more about spectroscopy

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