All categories

2 years ago

Which spectroscopic tool would be best for distinguishing a sample of 1,2-dichloropropane from 1,2-dibromopropane?

Chemistry

1 answer:

german2 years ago

4 0

The NMR spectroscopy will be used for distinguishing a sample of 1,2-dichloropropane from 1,2-dibromopropane.

A spectroscopic method for observing the local magnetic fields surrounding atomic nuclei seems to be nuclear magnetic resonance spectroscopy, also referred to as magnetic resonance spectroscopy as well as NMR spectroscopy.

The identification and study of organic molecules benefit greatly from nuclear magnetic resonance (NMR) spectroscopy. This type of spectroscopy has a straightforward underlying theory. Numerous atom types' nuclei behave like small magnets and frequently align themselves in magnetic fields.

Therefore, the NMR spectroscopy will be used for distinguishing a sample of 1,2-dichloropropane from 1,2-dibromopropane.

To know more about spectroscopy

brainly.com/question/5402430

#SPJ4

You might be interested in

If 1495 J of heat is needed to raise the temperature of a 319 g sample of a metal from 55.0°C to 66.0°C, what is the specific he

Olegator [25]

The specific heat capacity of the metal is calculated using the following formula
Q(heat)= MC delta T
Q= 1495 j
c= specific heat capacity =?
M(mass)=319 g
delta T = change in temperature = 66-55 =11 c
by making c the subject of the formula

C=Q /M delta T
c= 1495 j/ 319 g x 11 c =0.426 j/g/c

3 0

3 years ago

Atoms of elements in the same group have the same number of

tresset_1 [31]

Answer:

The elements of same group have similar chemical properties because they have same number of valence electrons.

Explanation:

6 0

4 years ago

The overall reaction taking place is shown in the equation below

algol [13]

A. The maximum possible mass of sodium that can be produced is 47.18 Kg

B. The percentage yield of the reaction is 80.6%

<h3>Determination of the mass of NaCl and Na </h3>

We'll begin by calculating the mass of NaCl that reacted and the mass of Na obtained from the balanced equation.

2NaCl –> 2Na + Cl₂

Molar mass NaCl = 23 + 35.5 = 58.5 g/mol

Mass of NaCl from the balanced equation = 2 × 58.5 = 117 g = 117 / 1000 = 0.117 Kg

Molar mass of Na = 23 g/mol

Mass of Na from the balanced equation = 2 × 23 = 46 g = 46 / 1000 = 0.046 Kg

SUMMARY

From the balanced equation above,

0.117 Kg of NaCl reacted to produce 0.046 Kg of Na.

<h3>A. How to determine mass of Na produced </h3>

From the balanced equation above,

0.117 Kg of NaCl reacted to produce 0.046 Kg of Na.

Therefore,

120 Kg of NaCl will react to produce = (120 × 0.046) / 0.117 = 47.18 Kg of Na

Thus, the maximum mass of Na produced is 47.18 Kg.

<h3>B. How to determine the percentage yield </h3>

Actual yield = 38.05 Kg
Theoretical yield = 47.18 Kg

Percentage yield =?

Percentage yield = (Actual / Theoretical) × 100

Percentage yield = (38.05 / 47.18) × 100

Percentage yield = 80.6%

Learn more about stoichiometry:

brainly.com/question/14735801

7 0

3 years ago

4 Identify What are the starting materials

Natalka [10]

Answer:

Detail is given below.

Explanation:

Photosynthesis:

Reactants = Carbon dioxide + water + energy

Products = glucose + oxygen

Chemical equation:

6H₂O + 6CO₂ + energy → C₆H₁₂O₆ + 6O₂

It is the process in which in the presence of sun light and chlorophyll by using carbon dioxide and water plants produce the oxygen and glucose.

water is supplied through the roots, carbon dioxide collected through stomata and sun light is capture by chloroplast.

Cellular respiration:

Reactants = Glucose + oxygen

Products = carbon dioxide + water + 38ATP

Chemical equation:

Glucose + oxygen → carbon dioxide + water + 38ATP

It is the breakdown of glucose molecule in the presence of oxygen to yield large amount of energy. Water and carbon dioxide are also produced as a byproduct.

7 0

3 years ago

The volume of a gas at 99.6 kPa and 24°C is 4.23 L. What volume will it occupy at 93.3 kPa ?

yuradex [85]

The volume is increased to 4.52 L on decreasing the pressure to 93.3 kPa.

Explanation:

As per Boyle's law, the volume occupied by gas particles will be inversely proportional to the pressure experienced by those particles at constant temperature.

$V=\frac{1}{P}$

So in the present problem, the volume of gas at pressure P₁ = 99.6 kPa is given as V₁ = 4.23 L. The temperature is kept constant at 24°C. Then, if the pressure is decreased to 93.3 kPa, then the volume is tend to increase due to Boyle's law.

So let us consider the new pressure be P₂ = 93.3 kPa and the new volume has to be found.

Then using Boyle's law, $P_{1} V_{1} = P_{2} V_{2}$

Then, $V_{2}=\frac{P_{1} V_{1} }{P_{2} }$

So, $V_{2}=\frac{99.6*1000*4.23}{93.3*1000}=4.52 L$

Thus, the volume is increased to 4.52 L on decreasing the pressure to 93.3 kPa.

6 0

4 years ago