Answer: -11s & -14t
Step-by-step explanation:
Answer:
![\left[\begin{array}{cccc}1&0&1&|-1\\-3&-9&3&|27\\3&2&0&|-2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%261%26%7C-1%5C%5C-3%26-9%263%26%7C27%5C%5C3%262%260%26%7C-2%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Given [Missing from the question]
![\left[\begin{array}{cccc}1&0&1&|-1\\1&3&-1&|-9\\3&2&0&|-2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%261%26%7C-1%5C%5C1%263%26-1%26%7C-9%5C%5C3%262%260%26%7C-2%5Cend%7Barray%7D%5Cright%5D)
Required

This implies that, we form a new matrix where the second row of the new matrix is a product of -3 and the second row of the previous matrix.
So, we have:
![Initial =\left[\begin{array}{cccc}1&0&1&|-1\\1&3&-1&|-9\\3&2&0&|-2\end{array}\right]](https://tex.z-dn.net/?f=Initial%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%261%26%7C-1%5C%5C1%263%26-1%26%7C-9%5C%5C3%262%260%26%7C-2%5Cend%7Barray%7D%5Cright%5D)
![New =\left[\begin{array}{cccc}1&0&1&|-1\\-3*1&-3*3&-3*-1&|-3*-9\\3&2&0&|-2\end{array}\right]](https://tex.z-dn.net/?f=New%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%261%26%7C-1%5C%5C-3%2A1%26-3%2A3%26-3%2A-1%26%7C-3%2A-9%5C%5C3%262%260%26%7C-2%5Cend%7Barray%7D%5Cright%5D)
![New =\left[\begin{array}{cccc}1&0&1&|-1\\-3&-9&3&|27\\3&2&0&|-2\end{array}\right]](https://tex.z-dn.net/?f=New%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%261%26%7C-1%5C%5C-3%26-9%263%26%7C27%5C%5C3%262%260%26%7C-2%5Cend%7Barray%7D%5Cright%5D)
Answer:
2286
Step-by-step explanation:
Hope this helps you.
the right answer to the question is catch me on the root mean square velocity of gas molecule when measured by galvanometer to produce circular egg in the presence of light under blanket.