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2 years ago

8

Which equation represents a linear equation

2 answers:

tensa zangetsu [6.8K]2 years ago

8 0

Answer:

I'm thinking it's A or C

Step-by-step explanation:

I'm sorry I can't decide ;-;

Oduvanchick [21]2 years ago

6 0

Answer:

The 4th answer.

Step-by-step explanation:

It has the equivalence that each point will be substracted 5 from y and 20 from x, but it won't change the line of the result. Sure, the position, but not the line.

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Is 5400 perfect square?if not how it should cames 5400 by division

kap26 [50]

Answer:

73.4846922835 = 73.5 and no it is not a perfect square 5400/100 = 54

8 0

2 years ago

In the expression 5y+4x2 what is the coefficient

MariettaO [177]

Answer:heyya

Step-by-step explanation:

<h3>coefficient means the number before the variables...the coefficient of y is 5..i dont know whether that is X or multiplication sign..if it is the variable X raise to the power 2 then the coefficient of X raise to the power 2 is 4..</h3><h3>hope it helps</h3>

8 0

3 years ago

Solve the oblique triangle where side a has length 10 cm, side c has length 12 cm, and angle beta has measure thirty degrees. Ro

Ugo [173]

Answer:

$Side\ B = 6.0$

$\alpha = 56.3$

$\theta = 93.7$

Step-by-step explanation:

Given

Let the three sides be represented with A, B, C

Let the angles be represented with $\alpha, \beta, \theta$

[See Attachment for Triangle]

$A = 10cm$

$C = 12cm$

$\beta = 30$

What the question is to calculate the third length (Side B) and the other 2 angles ( $\alpha\ and\ \theta$ )

Solving for Side B;

When two angles of a triangle are known, the third side is calculated as thus;

$B^2 = A^2 + C^2 - 2ABCos\beta$

Substitute: $A = 10$ , $C =12$ ; $\beta = 30$

$B^2 = 10^2 + 12^2 - 2 * 10 * 12 *Cos30$

$B^2 = 100 + 144 - 240*0.86602540378$

$B^2 = 100 + 144 - 207.846096907$

$B^2 = 36.153903093$

Take Square root of both sides

$\sqrt{B^2} = \sqrt{36.153903093}$

$B = \sqrt{36.153903093}$

$B = 6.0128115797$

$B = 6.0$ <em>(Approximated)</em>

Calculating Angle $\alpha$

$A^2 = B^2 + C^2 - 2BCCos\alpha$

Substitute: $A = 10$ , $C =12$ ; $B = 6$

$10^2 = 6^2 + 12^2 - 2 * 6 * 12 *Cos\alpha$

$100 = 36 + 144 - 144 *Cos\alpha$

$100 = 36 + 144 - 144 *Cos\alpha$

$100 = 180 - 144 *Cos\alpha$

Subtract 180 from both sides

$100 - 180 = 180 - 180 - 144 *Cos\alpha$

$-80 = - 144 *Cos\alpha$

Divide both sides by -144

$\frac{-80}{-144} = \frac{- 144 *Cos\alpha}{-144}$

$\frac{-80}{-144} = Cos\alpha$

$0.5555556 = Cos\alpha$

Take arccos of both sides

$Cos^{-1}(0.5555556) = Cos^{-1}(Cos\alpha)$

$Cos^{-1}(0.5555556) = \alpha$

$56.25098078 = \alpha$

$\alpha = 56.3$ <em>(Approximated)</em>

Calculating $\theta$

Sum of angles in a triangle = 180

Hence;

$\alpha + \beta + \theta = 180$

$30 + 56.3 + \theta = 180$

$86.3 + \theta = 180$

Make $\theta$ the subject of formula

$\theta = 180 - 86.3$

$\theta = 93.7$

5 0

3 years ago

Explain how you can how do you rename 5400 as hundreds

umka2103 [35]

I think it is fifty-four hundred

8 0

3 years ago

Find the value.plzzz I will mark as the brillianest plzzzzzzzzzzzzzzzzzzzz

Aleks [24]

Answer:

n= 75

y= 75

z= 50

p= 105

other n across from p= 105

Step-by-step explanation:

n and y are the same since the triangle is isoseles.

p is supplemetary to n

z and 50 are opposites in a quadrilateral

7 0

3 years ago