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finlep [7]
3 years ago
5

Five percent of canned goods get bumps or dents in the cans during manufacturing. Let X = the number of cans that are inspected

before one with a bump or dent is found.
What is the probability that more than 3 cans are inspected before one with a bump or dent is found?

Round to 4 decimal places.
Mathematics
1 answer:
Ainat [17]3 years ago
5 0

Answer:

0.8574

Step-by-step explanation:

I got it correct1

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Can you plz help me????????
Arada [10]
It is 91 because I know, I know because I know
6 0
3 years ago
Read 2 more answers
Assume that the helium porosity (in percentage) of coal samples taken from any particular seam is normally distributed with true
IgorLugansk [536]

Answer:

(a) 95% confidence interval for the true average porosity of a certain seam is [4.52 , 5.18].

(b) 98% confidence interval for the true average porosity of a another seam is [4.12 , 4.99].

Step-by-step explanation:

We are given that the helium porosity (in percentage) of coal samples taken from any particular seam is normally distributed with true standard deviation 0.75.

(a) Also, the average porosity for 20 specimens from the seam was 4.85.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

                      P.Q. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample average porosity = 4.85

            \sigma = population standard deviation = 0.75

            n = sample of specimens = 20

            \mu = true average porosity

<em>Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about population standard deviation.</em>

<u>So, 95% confidence interval for the true mean, </u>\mu<u> is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                                     of significance are -1.96 & 1.96}  

P(-1.96 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 1.96) = 0.95

P( -1.96 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} < 1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

P( \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ]

                                            = [ 4.85-1.96 \times {\frac{0.75}{\sqrt{20} } } , 4.85+1.96 \times {\frac{0.75}{\sqrt{20} } } ]

                                            = [4.52 , 5.18]

Therefore, 95% confidence interval for the true average porosity of a certain seam is [4.52 , 5.18].

(b) Now, there is another seam based on 16 specimens with a sample average porosity of 4.56.

The pivotal quantity for 98% confidence interval for the population mean is given by;

                      P.Q. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample average porosity = 4.56

            \sigma = population standard deviation = 0.75

            n = sample of specimens = 16

            \mu = true average porosity

<em>Here for constructing 98% confidence interval we have used One-sample z test statistics as we know about population standard deviation.</em>

<u>So, 98% confidence interval for the true mean, </u>\mu<u> is ;</u>

P(-2.3263 < N(0,1) < 2.3263) = 0.98  {As the critical value of z at 1% level

                                                   of significance are -2.3263 & 2.3263}  

P(-2.3263 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 2.3263) = 0.98

P( -2.3263 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} <  2.3263 ) = 0.98

P( \bar X-2.3263 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+2.3263 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.98

<u>98% confidence interval for</u> \mu = [ \bar X-2.3263 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+2.3263 \times {\frac{\sigma}{\sqrt{n} } } ]

                                            = [ 4.56-2.3263 \times {\frac{0.75}{\sqrt{16} } } , 4.56+2.3263 \times {\frac{0.75}{\sqrt{16} } } ]

                                            = [4.12 , 4.99]

Therefore, 98% confidence interval for the true average porosity of a another seam is [4.12 , 4.99].

7 0
3 years ago
Helpp with this its for a test review and I gotta turn it in quick
lesya [120]

Answer: 0.5

***If you found my answer helpful, please give me the brainliest. :) ***

5 0
2 years ago
Read 2 more answers
Z +9&gt; 22<br> Simplify your answer as much as possible.
Aleonysh [2.5K]

Answer:

z > 13

Step-by-step explanation:

Subtract 9 from 22.

z > 13

6 0
3 years ago
Robert mixed 113 liters of blue paint with 123 liters of red paint to make 3 liters of purple paint. To make a new batch of purp
MAVERICK [17]

Answer:

Blue =1\frac{3}{5}

Step-by-step explanation:

Given

Blue = 1\frac{1}{3}

Red = 1\frac{2}{3}

Required

Determine the amount of blue paint when Red = 2

To do this, we make use of the following equivalent ratios

Ratio = Blue : Red

When  Blue = 1\frac{1}{3} and  Red = 1\frac{2}{3}

Ratio = 1\frac{1}{3} : 1\frac{2}{3}

When Red = 2

Ratio = Blue : 2

Equate both ratios

Blue : 2 = 1\frac{1}{3} : 1\frac{2}{3}

Convert to division

\frac{Blue}{2} =1\frac{1}{3} / 1\frac{2}{3}

Convert fractions to improper fraction

\frac{Blue}{2} =\frac{4}{3} / \frac{5}{3}

\frac{Blue}{2} =\frac{4}{3} * \frac{3}{5}

\frac{Blue}{2} =\frac{4}{5}

Make Blue the subject

Blue =\frac{4}{5}*2

Blue =\frac{8}{5}

Blue =1\frac{3}{5}

4 0
3 years ago
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