You know where the glacier is now, and how far it moves in
one year. The question is asking how close to the sea it will be
after many years.
Step-1 ... you have to find out how many years
Step-2 ... you have to figure out how far it moves in that many years
Step-3 ... you have to figure out where it is after it moves that far
The first time I worked this problem, I left out the most important
step ... READ the problem carefully and make SURE you know
the real question. The first time I worked the problem, I thought
I was done after Step-2.
============================
Step-1: How many years is it from 2010 to 2030 ?
(2030 - 2010) = 20 years .
Step-2: How far will the glacier move in 20 years ?
It moves 0.004 mile in 1 year.
In 20 years, it moves 0.004 mile 20 times
0.004 x 20 = 0.08 mile
Step-3: How far will it be from the sea after all those years ?
In 2010, when we started watching it, it was 6.9 miles
from the sea.
The glacier moves toward the sea.
In 20 years, it will be 0.08 mile closer to the sea.
How close will it be ?
6.9 miles - 0.08 mile = 6.82 miles (if it doesn't melt)
Letter c is an operation.
Addition
Answer:
Step-by-step explanation:
Given
Solving (a): Write as inverse function
Represent a(d) as y
Swap positions of d and y
Make y the subject
Replace y with a'(d)
Prove that a(d) and a'(d) are inverse functions
and
To do this, we prove that:
Solving for 
Substitute 
for d in
Solving for: 
Substitute 5d - 3 for d in
Add fractions
Hence:
Answer:
23760 pounds
Step-by-step explanation:
396 passengers
60 pounds for each passenger
total pounds plane can carry=passengers × pounds
= 396×60
= 23760 pounds
....
