Answer a is the correct one
Answer:
Explanation:
An iodide ion is the ion I−. Compounds with iodine in formal oxidation state −1 are called iodides.
In a solid, the molecules are packed together, keeping shape. Liquid molecules are looser, and fit to the container they are in. Gas molecules are sporadic, and expand to fit their container
C. Metals higher in the series will replace metal ions in solution that
are lower in the series.
Explanation:
The activity series of metals shows the extent of reactivity of different metals.
On the activity series, the most reactive metals are located higher up on the able whereas the less reactive ones are found at the bottom of the series.
- We can tell if single displacement reactions will occur by simply looking at the reactivity series.
- Metals that are more reactive will displace the ones that are not very reactive that are positioned down the series. Such a reaction will occur.
- Metals lower in the series cannot displace the ones on top because they are less reactive. Such a reaction will not occur.
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Answer:
See explanation and image attached
Explanation:
The reaction of (R)-2-chloro-3-methylbutane with potassium tert-butoxide yields a monosubstituted alkene .
Since the base is bulky, the Hoffman product predominates because attack occurs at the less hindered carbon atom to yield the major product as shown.
The alkene reacts with HBr at the secondary carbon atom to yield a carbocation intermediate which is flat and planar. Attack on either face of the carbocation yields a racemic mixture of the (2R) and (2S) products.
Rearrangement of the carbocation to yield a tertiary carbocation gives the 2-bromo-2-methyl butane product as shown in the image attached.