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Rama09 [41]
3 years ago
11

If a rock sample has a mass of 2.7g and a volume of 1.1cm^3 what type of rock is it

Chemistry
2 answers:
ruslelena [56]3 years ago
7 0

Answer: Limestone or Rheolyte

Explanation:

The density of the given rock sample = mass of the sample/ volume of the sample

= 2.7/1.1 g/cm3

=2.5 g/cm3

From text: Alden, Andrew. "Densities of Common Rocks and Minerals." ThoughtCo, Jan. 23, 2020, thoughtco.com/densities-of-common-rocks-and-minerals-1439119.

Limestone has density range 2.3 - 2.7 (g/cm3)

Rheolyte has density range 2.4 - 2.6 (g/cm3)

The average density of each rock is 2.5 (g/cm3)

Therefore, base on density, the rock sample could be Limestone or Rheolyte

Vera_Pavlovna [14]3 years ago
5 0

Answer:

The rock is heavier than water and when put into water it will sink.

Explanation:

Given data:

Mass of rock = 2.7 g

Volume = 1.1 cm³

Type of rock = ?

Solution:

From given data we can calculate the density of rock.

If the density of rock is higher than the density of water it means the rock is heavier than water.

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Symbol:

The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.

d = m/v

d = 2.7 g/ 1.1 cm³

d = 2.5 g/cm³

density of water is 1 g/cm³. The rock is heavier than water and when put into water it will sink.

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Answer:

B. How much energy it takes to heat a substance

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The substances with higher value of specific heat capacity require more heat to raise the temperature by one degree as compared the substances having low value of specific heat capacity. For example,

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3 years ago
Dimethyl sulfoxide is an important polar aprotic solvent that can dissolve both polar and nonpolar compounds and is miscible in
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Answer:

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Allushta [10]
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1 mole of an ideal gas under Standard Temperature and Pressure occupies 22,4 L so the calculations are as follows:

0,0459 mol N_2* \frac{22,4 L}{1 mol N_2}= 1,028 L

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