Question

A certain shade of blue has a frequency of 7.35 × 1014 Hz. What is the energy of exactly one photon of this light?

Answer 1

Solution:

According to the formula of energy we know that

E = hf, where h is Planck's constant,  

6.63×10−34 J•s. This calculation is for one photon.  

E = 4.873 * 10^ -19 J.

This is the required energy for one Photon.

Answer 2

Energy of photon is equal to the product of Planck's constant (h) and frequency$\nu$.

The mathematical expression is :

$E=h\nu$

where,

E = energy of photon

h = Planck's constant ($6.626\times 10^{-34}Js$)

$\nu$ = frequency of light ($7.35 \times 10^{14} Hz$)

Plug in the values,

$E=(6.626\times 10^{-34}Js)\times (7.35 \times 10^{14} Hz)$

= $48.7011 \times 10^{-20} JsHz$

Now, Hz = inverse of second

Energy of photon = $48.7011 \times 10^{-20} J$ or $4.87011 \times 10^{-19} J$

Thus, energy of photon is equal to $4.87011 \times 10^{-19} J$