Answer:
0.441 L
Explanation:
At constant pressure, Using Charle's law :-
Given ,
V₁ = 0.500 L
V₂ = ?
T₁ = 25.0 °C
T₂ = -10.0 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (25 + 273.15) K = 298.15 K
T₂ = (-10 + 273.15) K = 263.15 K
Using above equation as:
<u>New volume = 0.441 L</u>
Answer: The volume of ethanolamine the student should pour out is 
Explanation:
To calculate the volume of ethanolamine we use the equation:

Density of ethanolamine = 
Mass of ethanolamine = 10.0 g
Volume of ethanolamine = ?
Putting values in above equation, we get:

Thus the volume of ethanolamine the student should pour out is 
Answer:
The decimal point in each number
Explanation:
Answer:
This is the same order as the definitions
1.
5.
3.
2.
4.
Hope it helps
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