Answer:
107%
Step-by-step explanation:
because if we look at the x-axis, Discount (%)
and look at 35 which is between 30 and 40
and start going up we get near 100
so
107%
or?
we use the two points and with that we find the slope first

plug in (20,62) and (10,32)
equals

simplify to 3
then we use
y - y1 = m (x - x1)
y - 62 = 3 (x - 20)
y - 62 = 3x - 60
add 60 from both sides
y - 2 = 3x
add 2 to both sides
y=3x+2
then plug in 35
y= 3(35) + 2
which is
107
Answer: 360minutes
Step-by-step explanation:
Speed = space/time ; time = space/speed
space = 600km
speed: 100km/h
time = 600km/100km/h = 6hours
Since 1hour = 60minutes
6hours = 6x60minutes = 360 minutes
Answer: 360minutes
<h2><em>Spymore</em></h2>
A set of ordered pairs is called a relation. The set of all first components of the ordered pairs of a relation is the domain of the relation, and the set of all second components of the ordered pairs is the range of the relation. :)
Answer: positive
Step-by-step explanation: it’s positive because if you multiply two negative numbers they cancel each other out and it makes a positive number
Answer:
We want a polynomial of smallest degree with rational coefficients with zeros in
,
and -3. The last root gives us the factor (x+3). Hence, our polynomial is

where
is a polynomial with rational coefficients and roots
and
. The root
gives us a factor
, but in order to obtain rational coefficients we must consider the factor
.
An analogue idea works with
. For convenience write
. This gives the factor
. Hence,

Notice that
. So, in order to satisfy the last condition we divide by 3 the whole polynomial, without altering its roots. Finally, the wanted polynomial is

Step-by-step explanation:
We must have present that any polynomial it's determined by its roots up to a constant factor. But here we have irrational ones, in order to eliminate the irrational coefficients that a factor of the type
will introduce in the expression, we need to multiply by its conjugate
. Hence, we will obtain
that have rational coefficients. Finally, the last condition is given with the intention to fix the constant factor. Usually it is enough to evaluate in the point and obtain the necessary factor.