Use the rules to evaluate or simplify. Write without negative exponents.

1 answer:

7 0

(y^-5) / (y^-2)
Flip fraction and get rid of the negative from the exponents (you can do that!)
(y^2) / (y^5)
(y * y) / (y * y * y * y * y)
Cancel y's
1 / (y * y * y)
1 / (y^3)

That's your answer.
Have an awesome day! :)

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What’s a line equation passing through (14,-8) and (24,-3)

Nataly_w [17]

$\bf (\stackrel{x_1}{14}~,~\stackrel{y_1}{-8})\qquad (\stackrel{x_2}{24}~,~\stackrel{y_2}{-3}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-3}-\stackrel{y1}{(-8)}}}{\underset{run} {\underset{x_2}{24}-\underset{x_1}{14}}}\implies \cfrac{-3+8}{10}\implies \cfrac{5}{10}\implies \cfrac{1}{2}$

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-8)}=\stackrel{m}{\cfrac{1}{2}}(x-\stackrel{x_1}{14}) \\\\\\ y+8=\cfrac{1}{2}x-7\implies y=\cfrac{1}{2}x-15$