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dedylja [7]
3 years ago
11

Name the values of the given digits 4s in 244

Mathematics
1 answer:
alexgriva [62]3 years ago
8 0
Hundred and tens. I think !!!!!!!!!?????

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Solve using they law of exponents <br> x^2 x x^-5
pentagon [3]

Answer:

−103

Step-by-step explanation:

6 0
3 years ago
1. Mrs. Jones picks 3 flowers a day starting on Monday. How many does she have by Sunday?
Aleks04 [339]

Answer:

1. 18

2. 2412

Step-by-step explanation:

1. Monday 3

Tuesday 6

Wensday 9

Thursday 12

Friday 15

Sunday 18

_____________________________________________________

2.

603*4=2412

3 0
3 years ago
Please find the exact length of the midsegment of trapezoid JKLM with vertices J(6, 10), K(10, 6), L(8, 2), and M(2, 2). Thank y
I am Lyosha [343]

Answer:

the exact length of the midsegment of trapezoid JKLM  = \mathbf{ = 3 \sqrt{5} } i.e 6.708 units on the graph

Step-by-step explanation:

From the diagram attached below; we can see a graphical representation showing the mid-segment of the trapezoid JKLM. The mid-segment is located at the line parallel to the sides of the trapezoid. However; these mid-segments are X and Y found on the line JK and LM respectively from the graph.

Using the expression for midpoints between two points to determine the exact length of the mid-segment ; we have:

\mathbf{ YX = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} }

\mathbf{ YX = \sqrt{(8-5)^2+(8-2)^2} }

\mathbf{ YX = \sqrt{(3)^2+(6)^2} }

\mathbf{ YX = \sqrt{9+36} }

\mathbf{ YX = \sqrt{45} }

\mathbf{ YX = \sqrt{9*5} }

\mathbf{ YX = 3 \sqrt{5} }

Thus; the exact length of the midsegment of trapezoid JKLM  = \mathbf{ = 3 \sqrt{5} } i.e 6.708 units on the graph

8 0
3 years ago
Can someone please help me with this?
ddd [48]

Answer:

b

Step-by-step explanation:

3 0
3 years ago
1+4=5 2+5=12 3+6=21 8+11=?
satela [25.4K]
That whole eqation is 40
6 0
3 years ago
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