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Mila [183]
3 years ago
11

A bag contains 7 red marbles, 8 blue marbles, and 5 green marbles. Mara randomly chose a marble, then she put it back and random

ly chose another marble. What is the probability that she chose 2 blue marbles? Answers in decimal form please.
Mathematics
1 answer:
Sindrei [870]3 years ago
3 0
7 + 8 + 5 = 20 total marbles

8 blue

probability of picking a blue marble = 8/20, reduces to 2/5 = 0.40

since she puts the first marble back, the 2nd pick is the same probability as the first one

so the probability of picking 2 blue would be 0.40 x 0.40 = 0.16
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Ad libitum [116K]

Answer:

$0.13

Step-by-step explanation:

7.98/60 = 0.133

round down to 0.13

8 0
3 years ago
Read 2 more answers
Find the Taylor series for f(x) centered at the given value of a. (Assume that f has a power series expansion. Do not show that
Kobotan [32]

Answer:

Here we just want to find the Taylor series for f(x) = ln(x), centered at the value of a (which we do not know).

Remember that the general Taylor expansion is:

f(x) = f(a) + f'(a)*(x - a) + \frac{1}{2!}*f''(a)(x -a)^2 + ...

for our function we have:

f'(x) =  1/x

f''(x) = -1/x^2

f'''(x) =  (1/2)*(1/x^3)

this is enough, now just let's write the series:

f(x) = ln(a) +  \frac{1}{a} *(x - a) - \frac{1}{2!} *\frac{1}{a^2} *(x - a)^2 + \frac{1}{3!} *\frac{1}{2*a^3} *(x - a)^3 + ....

This is the Taylor series to 3rd degree, you just need to change the value of a for the required value.

3 0
3 years ago
If Angle 4 = 6x+8 and Angle 3 = 20x+16 find the measure of all Four Angles
Rudik [331]

Answer:

40 on edge

Step-by-step explanation:

2021

5 0
2 years ago
Find a closed form for the generating function for each of these sequences. (assume a general form for the terms of the sequence
noname [10]
There really is no single "obvious" choice here...

Possibly the sequence is periodic, with seven copies of -1 followed by six copies of 0, or perhaps seven -1s and seven 0s. Or maybe seven -1s, followed by six 0s, then five 1s, and so on, but after a certain point it would seem we have to have negative copies of a number, which is meaningless.

Or maybe it's not periodic, and every seventh value in the sequence is incremented by 1? Who knows?

I'll go ahead and assume the latter case, that the sequence is not periodic, since that's technically somewhat easier to manage. We can assign the following rule to the n-th term in the sequence:

\{a_n\}=\{-1,\ldots,-1,0,\ldots,0,1,\ldots,1,2,\ldots,2,3,\ldots\}
\implies a_n=\left\lfloor\dfrac n7\right\rfloor-1

for n\ge0.

So the generating function for this sequence might be

G(a_n;x)=\displaystyle\sum_{n\ge0}\left(\left\lfloor\frac n7\right\rfloor-1\right)x^n

As to what is meant by "closed form", I'm not sure. Would this answer be acceptable? Or do you need to find a possibly more tractable form for the coefficient not in terms of the floor function?
4 0
3 years ago
Determine if the function is continuous to its domain
Maurinko [17]

Yes, it is continuous to its domain

<h2>Explanation:</h2><h2></h2>

In order to find the domain of the function we need to get the restrictions:

1. From natural log:

x>0

2. From quotient:

x\neq 0

Matching these two restrictions the domain is:

x\in (0,\infty)

So the function is continuous to its domain because is defined for every x-value in the interval (0, \infty))

<h2>Learn more:</h2>

Functions: brainly.com/question/12891789

#LearnWithBrainly

6 0
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